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Sladkaya [172]
3 years ago
7

Complete the square 2x2- 12x+ 26 = 10

Mathematics
1 answer:
Mariana [72]3 years ago
4 0
2x^2-12x+26=10\ \ \ | subtract\ 10\\\\
2x^2-12x+16=0\ \ \ | divide\ by\ 2\\\\
x^2-6x+8=0\\\\
put\ into\ form:\ (x+d)^2+c=0\\
-6x=2xd\ \ \ | divide\ by\ x\\
d=-3\\
8=d^2+c\\
8=9+c\ \ \ | subtract\ 9\\
c=-1\\\\
After\ completing\ the\ square:\\
(x-3)^2-1=0
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Answer:b) 4 cups

Step-by-step explanation:

8 0
2 years ago
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enyata [817]

Answer:

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7 0
3 years ago
Z=5x- 11y <br> can someone please help
Feliz [49]

Answer:

z+11y/5 = x

Step-by-step explanation:

Since you are solving for x, you want to isolate the variable. You do that by adding 11y to both sides, which cancels out the -11y. From that you should have z+11y = 5x. To cancel out the 5x you need to divide both sides by 5 to get z+11y/5 = x. Hope this helps :)

3 0
2 years ago
Huw has a maths test. the second question is:
xeze [42]

Huw's answer of 9 days is incorrect because more guests would finish the food in less time so the number of days for 30 guests is less than 6 days.

The number of days that the food can last 30 guests is 4 days.

<h3>How long will Seaview Hotel's food feed 30 guests?</h3>

More guests would eat the food faster which means that it would be finished in less days than the 6 days used by 20 guests.

To find the days the food would last 30 guests, use the inverse proportion formula:
= (Number of guests x Number of days food lasts for guests) / New number of guests

= (20 x 6) / 30

= 4 days

Full question is:

The only food provided for guests at Seaview Hotel is breakfast. The hotel has enough food to make breakfast for 20 guests for 6 days. How long would the food last 30 guests? You may assume each guest eats the same amount of food for breakfast.

Without working out the correct answer, explain why Huw’s answer of 9 days is incorrect.

Find out more on inverse proportion at brainly.com/question/1266676.

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5 0
2 years ago
Graph this parametric equation<br><br> x = 2t y = t + 5, -2 ≤ t ≤ 3
UNO [17]
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We start with the given </span>-2 ≤ t ≤ 3 then substitute y = t +5 by using the limits of the range:

at t = -2 ; y = -2 + 5 = 3
at t = 3, y = 3+5 = 8

for the second equation

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we group the points based on their original corresponding t's 

(3,-4) and (8,6) we just have to connect these points along with the internal points in between. The relationship should be linear.
6 0
3 years ago
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