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sergeinik [125]
4 years ago
15

There is a 30 g sample of Be-11. It has a half-life of about 14 seconds.How much will be left after 28 seconds?A.3.75 gB.7.5 gC.

15 gD.30 g
Chemistry
1 answer:
pshichka [43]4 years ago
5 0

Answer:

After 28 sec 7.5 grams of Be will be left

Explanation:

Given data:

Total amount of Be = 30 g

Half life of Be = 14 sec

Mass left after 28 sec = ?

Solution:

First of all we will calculate the number of half lives in 28 sec.

Number of half lives = T elapsed / half life

Number of half lives = 28 sec / 14 sec

Number of half lives = 2

AT time zero = 30 g

At first half life = 30 g/2 = 15 g

At second half life = 15 g/ 2 = 7.5 g

So after 28 sec 7.5 grams of Be will be left.

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Please hurry and tell the answer to:
Flura [38]

Answer:

6.50 g of Hydrogen

Explanation:

We know that in every 20.0g of sucrose, there are 1.30g of hydrogen.

We now have 100.0g of sucrose. 100.0g is 5x larger than the 20.0g sample, which is a 5 : 1 ratio. Applying this ratio to the amount of hydrogen, we would have 5*1.3g of hydrogen in the 100.0g of sucrose.

5*1.3 = 6.5, so our answer is that there are 6.50g of hydrogen in 100.0g of sucrose.

Hope this helps!

5 0
2 years ago
The thermostat in a refrigerator filled with cans of soft drinks malfunctions and the temperature of the refrigerator drops belo
butalik [34]

Answer:

B.

Explanation:

Water expands on freezing and there is more water in the diet drinks than in the other drinks.

5 0
3 years ago
Read 2 more answers
How many molecules would 3.45 moles of methane (CH4)
fenix001 [56]
How to answer the question? ⬇️
(Btw this is an example on how to solve it so just letting you know)

To answer this question, you must understand how to convert grams of a molecule into the number of molecules. To do this, you have to utilize the concepts of moles and molar mass.
A mole is just a unit of measurement. Avogadro's number is equal to
6.022
⋅
10
23
molecules/mole. This number is the number of molecules of a specific compound in which when you multiply the compound by it, it converts atomic mass into grams.
For example, one mole of hydrogen gas (
H
2
) or
6.022
⋅
10
23
molecules of
H
2
weighs 2.016 grams because one molecule of
H
2
has an atomic weight of 2.016.
So the overall solution for this problem is to use molar mass of
C
H
4
(methane) to convert grams of methane into moles of methane. Then, use Avogadro's number to convert moles of methane into molecules of methane.
One mole of methane equals 16.04 grams because a molecule of methane has an atomic weight of 16.04. The conversion factor will be 16.04 grams/mole.
48
g
C
H
4
⋅
1
m
o
l
C
H
4
16.04
g
C
H
4
⋅
6.022
⋅
10
23
m
c
l
s
C
H
4
1
m
o
l
C
H
4

When you multiple and divide everything out, you get
1.8021
⋅
10
24
molecules of
C
H
4

Notice this is a modified T-chart so the grams
C
H
4
cancels out when you do the first conversion, and the moles
C
H
4
cancels out when you do the second conversion. This leaves you with the unit molecules of
C
H
4
which corresponds to what the question asks.

This is something else and is not connected with the one above this comment.

The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles CH4, or 16.04246 grams.

Or

Therefore 3.4 grams of ammonia is equal to 0.1996359579590159 moles of ammonia. Multiplying this by 6.022 * 1023 we get 120220773882919374980000 molecules (or 1.2022 * 1023 molecules). ...
6 0
3 years ago
During a class demonstration the potassium exploded. Suggest what might have caused this to happen
tatiyna
Could’ve reacted with water as alkali metals are very reactive to water.
7 0
3 years ago
An ion is an atom with a net electrical charge due to ______.
Serga [27]
<span>the loss of one or more electrons & the addition of one of more electrons</span>
7 0
3 years ago
Read 2 more answers
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