1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sergeinik [125]
4 years ago
15

There is a 30 g sample of Be-11. It has a half-life of about 14 seconds.How much will be left after 28 seconds?A.3.75 gB.7.5 gC.

15 gD.30 g
Chemistry
1 answer:
pshichka [43]4 years ago
5 0

Answer:

After 28 sec 7.5 grams of Be will be left

Explanation:

Given data:

Total amount of Be = 30 g

Half life of Be = 14 sec

Mass left after 28 sec = ?

Solution:

First of all we will calculate the number of half lives in 28 sec.

Number of half lives = T elapsed / half life

Number of half lives = 28 sec / 14 sec

Number of half lives = 2

AT time zero = 30 g

At first half life = 30 g/2 = 15 g

At second half life = 15 g/ 2 = 7.5 g

So after 28 sec 7.5 grams of Be will be left.

You might be interested in
Rico and Bree are camping and have potatoes wrapped in foil to eat. Bree put her potato in the campfire for a while, but Rico di
inn [45]

Answer:

There is no difference because both potatoes are made of the same type of molecules.

5 0
2 years ago
If the density is 0.9g/cm3 and the volume is 1.5cm3 ? What is the Mass?
Mama L [17]

Answer:

1.35g

Explanation:

times the density and volume together to get the mass

0.9 x 1.5 = 1.35g

6 0
3 years ago
What is the pH of a solution with a H+ ion of 2×10-¹²?​
kap26 [50]

Answer:

11.7

Explanation:

The pH is the negative logarithm of the concentration of H+ ions. If the concentration is 2×10-¹² the the pH will be -log(2×10-¹²) which is 11.698 which can be round up to 11.7.

5 0
3 years ago
Determine the mass of oxygen produced in the decomposition of 25.0 g of potassium
Andrews [41]

Answer:

9.80g of O2.

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

2KClO3 —> 2KCl + 3O2

Step 2:

Determination of the mass of KClO3 that decomposed and the mass of O2 produced from the balanced equation. This is illustrated below:

Molar Mass of KClO3 = 39 + 35.5 + (16x3) = 122.5g/mol

Mass of KClO3 from the balanced equation = 2 x 122.5 = 245g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 3 x 32 = 96g.

From the balanced equation above, 245g of KClO3 decomposed to produce 96g of O2.

Step 3:

Determination of the mass of O2 produced in the decomposition of 25.0g of KClO3. This is illustrated below:

From the balanced equation above, 245g of KClO3 decomposed to produce 96g of O2.

Therefore, 25g of KClO3 will decompose to produce = (25x96)/245 =

9.80g of O2.

Therefore, 9.80g of O2 is produced from the decomposition of 25g of KClO3.

5 0
3 years ago
Which energy transformation took place?
Goshia [24]

Answer:

C

Explanation:

The battery is chemical energy. When it is used in the flashlight, it produces light and thermal energy

PLZ MARK BRAINLIEST :)

7 0
3 years ago
Read 2 more answers
Other questions:
  • When co2 levels are low and o2 levels are high, rubisco adds an o2 molecule to rubp. what are the consequences of this reaction?
    10·1 answer
  • Determine the number of ions produced in the dissociation of the compound listed. BaS
    12·2 answers
  • The mass of solute per 100 mL of solution is abbreviated as (m/v). Mass is not technically the same thing as weight, but the abb
    8·1 answer
  • How does an ion differ from an electrically-neutral atom?
    12·2 answers
  • Ultraviolet rays from the sun can cause
    7·1 answer
  • Which of the following best describes how forces affect matter?
    10·1 answer
  • Atoms of elements in the same group have the same number of (blank) This is why they have similar chemical properties.
    13·1 answer
  • If You are given 14 moles of C2H5OH(Ethanol) and 13 moles of O2( Oxygen), how
    13·1 answer
  • The atomic number of an element that has 9 protons 9 electrons and 10 neutrons is?
    13·1 answer
  • Calcule la formula empírica de la sustancia está compuesta por 18,4% de carbono 21,5% de nitrógeno y 60,1% de potasio
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!