Answer:
a. 75 mol O2
Explanation:
1 mol C2H6O -> 3 mol O2
25 mol C2H6O -> x
x= (25 mol C2H6O * 3 mol O2)/ 1 mol C2H6O
x= 75 mol O2
<span>S(s)+O2(g)→SO2(g), ΔHâ = -296.8kJ
SO2(g)+12O2(g)→SO3(g) , ΔHâ = -98.9kJ
H2(g) + 1/2 O2 (g) --------> H2O(l)ΔHâf = -285.8kJ
SO3(g) + H2O(l) --------> H2SO4, ΔHâ = -227.8 kJ .
All above steps are involved in the formation of H2SO4, therefore delta Hf for H2SO4 is [ -296.8+ (-98.9)+ (-285.8) +(-227.8)] = - 909.3 kj/mol
The energy required to form 1 mol H2SO4 fom its elements is - 909.3 kj / mol</span>
Answer:
Molarity = 1.4 M
Explanation:
Given data:
Density of acetic acid = 1.049 g/mL
Volume of acetic acid = 20.0 mL
Volume of solution = 250.0 mL (250/1000 = 0.25 L)
Molarity = ?
Solution:
Mass of acetic acid = density × volume
Mass of acetic acid = 1.049 g/mL × 20.0 mL
Mass of acetic acid = 20.98 g
Number of moles of acetic acid = mass/ molar mass
Number of moles of acetic acid = 20.98 g/ 60.052 g/mol
Number of moles of acetic acid = 0.35 mol
Molarity = number of moles / volume in L
Molarity = 0.35 mol / 0.25 L
Molarity = 1.4 M