Question

Given 7.65 mol AgNO3, determine the number of formula units.

Answer 1

Answer:

The number of formula units of silver nitrate is $4.61\times 10^{24}$.

Explanation:

Moles of silver nitrate = n = 7.65 mol

1 mole = $N_A=6.022\times 10^{23}$ atoms/ molecules/ ions

Let the number of formula units of silver nitrate be N.

$N=n\times N_A$

$N=7.65 mol\times 6.022\times 10^{23}=4.61\times 10^{24}$

The number of formula units of silver nitrate is $4.61\times 10^{24}$.