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3 years ago

I need help on this its due Monday

Chemistry

1 answer:

atroni [7]3 years ago

6 0

The properties of the elements can be determined from their electron configuration

<h3>Further explanation</h3>

Mg ⇒electron configuration :[Ne] 3s²

outer electron : 2 (3s²)

lose(2 electron)

charge : +2

cation (positive)

symbol : Mg²⁺

Br⇒electron configuration : [Ar] 4s²3d¹⁰4p⁵

outer electron : 7 (4s²4p⁵)

gain ( 1 electron)

charge : -1

anion (negative)

symbol : Br⁻

Helium⇒electron configuration : 1s²

outer electron : 2 (1s²)

stabil(no gain/no lose)

charge : 0

neutral

symbol : He

Nitrogen ⇒electron configuration : [He] 2s²2p³

outer electron : 5 ( 2s²2p³)

gain(3 electron)

charge : -3

anion

symbol : N³⁻

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rewona [7]

Answer:

Explanation:

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2 years ago

A Buffer Solution is 0.100 M in both HC7H5O2 and LiC7H5O2 and has a pH of 4.19. Which of the following pH values would you expec

luda_lava [24]

Answer: Nov 24, 2010 · A buffer solution is 0.100 M in both HC7H5O2 and LiC7H5O2 and has a pH of 4.19. Which of the following pH values would you expect from the addition of a small amount of a dilute solution of a strong base? A. 4.49 B.3.89 C.5.69 D. 3.69 E. There is not enough info to determine

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Jul 05, 2011

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4 years ago

150 mL of 0.25 mol/L magnesium chloride solution and 150 mL of 0.35 mol/L silver nitrate solution are mixed together. After reac

Murljashka [212]

Answer:

$0.175\; \rm mol \cdot L^{-1}$ .

Explanation:

Magnesium chloride and silver nitrate reacts at a $2:1$ ratio:

$\rm MgCl_2\, (aq) + 2\, AgNO_3\, (aq) \to Mg(NO_3)_2 \, (aq) + 2\, AgCl\, (s)$ .

In reality, the nitrate ion from silver nitrate did not take part in this reaction at all. Consider the ionic equation for this very reaction:

$\begin{aligned}& \rm Mg^{2+} + 2\, Cl^{-} + 2\, Ag^{+} + 2\, {NO_3}^{-} \\&\to \rm Mg^{2+} + 2\, {NO_3}^{-} + 2\, AgCl\, (s)\end{aligned}$ .

The precipitate silver chloride $\rm AgCl$ is insoluble in water and barely ionizes. Hence, $\rm AgCl\!$ isn't rewritten as ions.

Net ionic equation:

$\begin{aligned}& \rm Ag^{+} + Cl^{-} \to AgCl\, (s)\end{aligned}$ .

Calculate the initial quantity of nitrate ions in the mixture.

$\begin{aligned}n(\text{initial}) &= c(\text{initial}) \cdot V(\text{initial}) \\ &= 0.25\; \rm mol \cdot L^{-1} \times 0.150\; \rm L \\ &= 0.0375\; \rm mol \end{aligned}$ .

Since nitrate ions $\rm {NO_3}^{-}$ do not take part in any reaction in this mixture, the quantity of this ion would stay the same.

$n(\text{final}) = n(\text{initial}) = 0.0375\; \rm mol$ .

However, the volume of the new solution is twice that of the original nitrate solution. Hence, the concentration of nitrate ions in the new solution would be $(1/2)$ of the concentration in the original solution.

$\begin{aligned} c(\text{final}) &= \frac{n(\text{final})}{V(\text{final})} \\ &= \frac{0.0375\; \rm mol}{0.300\; \rm L} = 0.175\; \rm mol \cdot L^{-1}\end{aligned}$ .

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3 years ago

In an experiment, Lydia added 50 grams of sugar to 200 milliliters of water. She stirred the mixture, and the sugar eventually d

babymother [125]

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3 years ago

Read 2 more answers

Which of the following is not the same as 0.00684 kg?

olchik [2.2K]

kg and all the given units are units used to measure mass.

kg is the standard unit to measure mass

lets find the value of 0.00684 kg in all the given units

a. dkg

1 kg is equivalent to 100 decagram (dkg)

therefore 0.00684 kg is = 100 dkg/kg x 0.00684 kg = 0.684 dkg

this is not the given value therefore this choice is incorrect

b. 1 kg is equivalent to 1000 g

therefore 0.00684 kg = 1000 g/kg x 0.00684 kg = 6.84 g

this is the given value so this is correct

c. 1 kg is equivalent to 100 000 centigrams (cg)

therefore 0.00684 kg = 100 000 cg/kg x 0.00684 kg = 684 cg

this is the given value so this is also correct

d) 1 kg is equivalent to 1 000 000 mg

therefore 0.00684 kg = 1 000 000 mg/kg x 0.00684 kg = 6 840 mg

this too is correct

the incorrect answer is A. 0.0684 dkg

5 0

3 years ago

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