Answer: The options are not given, here are the options.
A. One species is much better competitor than the other.
B. Periodic disturbances allow for coexistence.
C. Two species tended to use different resources.
D. The two species experienced interference competition and not exploitative competition.
The correct option C.
Two species tended to use different resources.
Explanation:
From Gause experiments on competing paramecium pairs, He found out that most times both species persisted and sometimes only one did because the two species uses different resources.
Organisms normally compete for limited resources in order to survive and one intend to compete well while other suffer. Both in the case of competing paramecium pairs, the pair use different resources which make the to persist and survive well. Once the resource of one finishes, the other one will persist because it is still surviving on its available resources.
A phylogeny of the same taxa based only on morphological traits:
Some highly conserved genetic sequences can result in unrelated species appearing closely related in a molecular phylogeny, and not reflect the same pattern as the morphologic phylogeny.
Gene sequence changes may not result in morphological changes.
Gene sequences always provide more data than morphological traits.
Morphological analyses always provide more data because each morphological trait is the result of the expression of many genes.
The molecular data may be based on the analysis of introns, which aren't expressed and don't contribute to the evolutionary history of a group of taxa.
Why is molecular data more accurate?
Phylogenetic trees reconstructed from molecular sequences are often considered more reliable than those reconstructed from morphological characters, in part because convergent evolution, which confounds phylogenetic reconstruction, is believed to be rarer for molecular sequences than for morphologies
Learn more about molecular data :
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The conversion of light energy into chemical energy is dependent on the substance chlorophyll
Answer:
In glycolysis, the generation of ATP takes place at the time of the transformation of 1,3-bisphosphoglycerate to 3-phosphoglycerate and at the time of the transformation of phosphoenolpyruvate to pyruvate. However, when arsenate is used in place of phosphate it results in the generation of 1-arseno-3-phosphoenolpyruvate to pyruvate that further gets dissociated into 3-phosphoglycerate without generating any ATP.
However, in the process, the transformation of phosphoenolpyruvate to pyruvate does not get hampered, and therefore, the reaction will produce two ATP from one glucose. Although at the time of the preparatory phase of glycolysis, two ATPs are used that signifies that the net gain of ATP will be zero.
