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vredina [299]
3 years ago
6

How many germs does a dog have?

Biology
1 answer:
faltersainse [42]3 years ago
7 0
Short answer - Alot! 
Its pretty hard to count how much germs a dog has, "germ" is just a widely known term for bad bacteria, which infects spreads and repeats with whatever it touches. The amount of bacteria would depend on many things, if the dog is sick, if it just went to the dog park, if it was just bathed, and if it recently ate. This is any type of bacteria of course not just bad, There's bacteria in your stomach right now, helping you digest any food. The point is though, is that the germs a dog has is like asking how many stars are in each galaxy , you can only give an estimation, but it will always be affected by the condition of the galaxy, or in the case the dog.
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Why is it important for DNA to be duplicated before mitosis?
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Which cell organelles function resembles the function of the brain in higher animals
Stella [2.4K]

The nucleus of the cell

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Fill the punnett square below to show a cross between two between two guinea pig that Are heterozygous for the coat color
Soloha48 [4]
25% CC 25% cc 50% Cc
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4 years ago
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fredd [130]

Vascular plants appered during the same perod as mammals

Explanation:

3 0
3 years ago
Sickle-cell trait is caused by a single defective allele, but sickle-cell disease only occurs in individuals that are homozygous
Pavel [41]

Answer:

6,25%

Explanation:

Considering that the couple has a trait of sickle cell anemia, we know that both are heterozygous for the disease (Aa) and therefore can have children with the following genotypes:

Parents: Aa X Aa

Children: AA(A x A), Aa(A x a), Aa (a x A) and aa(a x a)

Knowing that sickle cell anemia only occurs in homozygous individuals, the probability for children to have the disease according to each crossing is:

A x A = 1/4 = 25%

A x a = 1/4 = 25%

a x A = 1/4 = 25%

a x a = 1/4 = 25%

The probability of forming each homozygous child (aa) is 1/4 or 25%. Since they are two children, the probability of both having sickle cell anemia is calculated by multiplying the probability of each, so:

1/4 × 1/4 = 1/16 = 0.0625 = 6.25%

It is concluded that the probability of a heterozygous couple for sickle cell anemia to have two children with the disease is 6.25%.

6 0
3 years ago
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