Answer:
Option C and D are false
Step-by-step explanation:
All the mentioned option are correct in the given scenario except option C and D.
The reason is that dose is categorized as nil, low and high so, dose is categorical variable. Also, number of tumors is quantitative variable because it can be meaningfully interpreted in numerical form. The number if tumors is discrete quantitative variable.
Now consider all options
A) Gender is categorical ; dose is ordinal
This option is true because gender can be categorized into male and female and also dose is ordinal because it has order i.e. nil,low and high.
B) Gender is discrete; weight is continuous
This option is false because gender can be a discrete variable and weight is continuous variable because it is measurable. So, the statement is true.
Option C and D are already discussed an option E is discussed in option B.
Answer:
y=6
Step-by-step explanation:
-6y+15=-21
-6y=-21-15 (it becomes negative on this side.)
-6y=-36 (divide both sides by -6.)
y=6
The track is a square with half circle on its right and left side. The area of the square is 128 feet². The length is 22.6 feet
<h3>How to illustrate the information?</h3>
It should be noted that the area of the square will be:
= x².
Therefore, 128 = x².
x ,= ✓128
x = 11.3
Therefore the radius of the circle will be:
= 11.3/2
= 5.65
The length of the truck will be:
= 11.3 + 5.65 + 5.65
= 22.6
The length is 22.6 feet
Learn more about square in:
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Injured runners train on a special track at a rehabilitation center. The track is a square with a half circle on its left and right sides. The area of the square is 128 square feet. What is the length of the track? Use the table to help you answer the questions.
Square 11.02 11.12 11.22 11.32 11.42 11.52
Value 121.0 123.2 125.4 127.7 130.0 132.3
Square 11.62 11.72 11.82 11.92 12.02
Value 134.6 136.9 139.2 141.6 144.0
1. Fill in the blanks to complete the description of the track.
The track has ____ sides of the square and the distance around
Answer:
x=8 or x=-2
Step-by-step explanation:
x²-16=6x
x²-6x-16=0
x²-8x+2x-16=0
x(x-8)+2(x-8)=0
(x-8)(x+2)=0
either,. or.
x-8=0 x+2=0
x=8 x=-2
