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Paha777 [63]
3 years ago
8

a local coffee shop sold out 1/3 of their coffee on monday. on tuesday they sold 5/6 of what rhey sold on monday. How many coffe

e grounds were sold on tuesday
Mathematics
1 answer:
ololo11 [35]3 years ago
6 0

Answer:

5/18

Step-by-step explanation:

1/3 on monday

5/6 more

1/3 times 5/6

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I think it is -10 i hope this helps
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You offer to do the dishes for your family for the next month. You suggest that they can pay you in one of three ways.
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I say number 2

Step-by-step explanation:

0.02 is 2 cents while 0.20 is twenty sense. That would make more sense

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Answer:

<em>Please follow;</em>

<em>Please follow;Hope you're having a splendiferous day.</em>

Step-by-step explanation:

1. 5÷½=10

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There are as many 5p coins as 1p coins in the bag.
nekit [7.7K]

Answer:

160

Step-by-step explanation:

In math, the word of means multiply. :)

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6 0
2 years ago
At a Psychology final exam, the scores are normally distributed with a mean 73 points and a standard deviation of 10.6 points. T
USPshnik [31]

Answer:

The score that separates the lower 5% of the class from the rest of the class is 55.6.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

\mu = 73, \sigma = 10.6

Find the score that separates the lower 5% of the class from the rest of the class.

This score is the 5th percentile, which is X when Z has a pvalue of 0.05. So it is X when Z = -1.645.

Z = \frac{X - \mu}{\sigma}

-1.645 = \frac{X - 73}{10.6}

X - 73 = -1.645*10.6

X = 55.6

The score that separates the lower 5% of the class from the rest of the class is 55.6.

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