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2 years ago

6

A seven digit number has 0 in the one's place a 6 in the ten thousand s place an 8 in the millions place and a fives in each of

the remaining places what is the number

1 answer:

vladimir2022 [97]2 years ago

4 0

8,565,550
just replace 5 with the number

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A tank has the shape of a rectangular prism with the dimensions shown. How much glass was used to make the tank. 34 in² 65 in² 1

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Answer: Find the surface area with the formula $SA = 2wl + 2lh + 2hw$

Step-by-step explanation:

<u><em> Since you did not provide the figure, I will give you a general explanation about how to solve this exercise.</em></u>

By definition, the surface area of a rectangular prism can be calculated with the formula shown below:

$SA = 2wl + 2lh + 2hw$

Where "SA" is the surface area of the rectangular prism, "w" is the width of the rectangular prism, "l" is the length and "h" is the height of the rectangular prism.

Therefore, if you know the length, the width and the height of the rectangular prism, you can follow these steps in order to calculate how much glass was used to make the tank. The procedure is:

Step 1: You must substitute the values of "l", "w" and "h" into the formula.

Step 2: Finally, you must evaluate in order to get the surface area of the rectangular prism (This value is the amount of square inches that was used to make the tank).

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2 years ago

A tank contains 240 liters of fluid in which 20 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu

Novosadov [1.4K]

Answer:

$A(t)=240-220e^{-\frac{t}{40}}$

Step-by-step explanation:

A tank contains 240 liters of fluid in which 20 grams of salt is dissolved.

Volume of the tank = 240 liters
Initial Amount of Salt in the tank, A(0)=20 grams

Brine containing 1 gram of salt per liter is then pumped into the tank at a rate of 6 L/min

$R_{in}=$ (concentration of salt in inflow)(input rate of fluid)

$R_{in}=(1\frac{gram}{liter})( 6\frac{Liter}{min})=6\frac{gram}{min}$

$R_{out}=$ (concentration of salt in outflow)(output rate of fluid)

$R_{out}=(\frac{A(t)}{240})( 6\frac{Liter}{min})\\R_{out}=\frac{A}{40}$

Rate of change of the amount of salt in the tank:

$\dfrac{dA}{dt}=R_{in}-R_{out}$

$\dfrac{dA}{dt}=6-\dfrac{A}{40}$

We then solve the resulting differential equation by separation of variables.

$\dfrac{dA}{dt}+\dfrac{A}{40}=6\\$The integrating factor: e^{\int \frac{1}{40}dt} =e^{\frac{t}{40}}\\$Multiplying by the integrating factor all through\\\dfrac{dA}{dt}e^{\frac{t}{40}}+\dfrac{A}{40}e^{\frac{t}{40}}=6e^{\frac{t}{40}}\\(Ae^{\frac{t}{40}})'=6e^{\frac{t}{40}}$

Taking the integral of both sides

$\int(Ae^{\frac{t}{40}})'=\int 6e^{\frac{t}{40}} dt\\Ae^{\frac{t}{40}}=6*40e^{\frac{t}{40}}+C, $(C a constant of integration)\\Ae^{\frac{t}{40}}=240e^{\frac{t}{40}}+C\\$Divide all through by e^{\frac{t}{40}}\\A(t)=240+Ce^{-\frac{t}{40}}$

Recall that when t=0, A(t)=20 (our initial condition)

$20=240+Ce^{-\frac{0}{40}}\\20-240=C\\C=-220\\$Therefore, the number A(t) of grams of salt in the tank at time t\\A(t)=240-220e^{-\frac{t}{40}}$

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Answer:

I think 75%.................

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Pani-rosa [81]

Cos (π/2 - x) = sin x = 3/5
tan x = sin x / cos x = 3/5 / 4/5 = 3/4
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cot x = 1/tan x = 1 / 3/4 = 4/3.

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<span>Let n = the number of pages not read
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