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3 years ago

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Sybil has 1/2 pizza left over. she wants to share the pizza with her 3 friends. what fraction of the pizza will sybil and her 3

friends receive

2 answers:

goldfiish [28.3K]3 years ago

5 0

Each friend will have $\frac{1}{6}$ because $\frac{1}{2} ÷ 3 = [tex] \frac{1}{6}$

Leni [432]3 years ago

5 0

Sybil and her 3 friends will receive ¹/₈ pizza

<h3>Further explanation</h3>

Order of Operations in Mathematics follow this following rule :

Parentheses
Exponents
Multiplication and Division
Addition and Subtraction

This rule is known as the PEMDAS method.

In working on a mathematical problem, we first calculate operation that is in parentheses, follow by exponentiation, then multiplication or division, and finally addition or subtraction.

Let us tackle the problem !

Let :

<em>Initial Amount of Pizza = X</em>

Sybil has 1/2 pizza left over → $\texttt{Sybil's Pizza} = \frac{1}{2}X$

<em>She wants to share the pizza with her 3 friends.</em>

We will divide the remaining pizza into 4 parts.

$\texttt{The portion of pizza each received} = \texttt{Sybil's Pizza} \div 4$

$\texttt{The portion of pizza each received} = \frac{1}{2}X \div 4$

$\texttt{The portion of pizza each received} = \frac{1}{2}X \times \frac{1}{4}$

$\texttt{The portion of pizza each received} = \frac{1}{8}X$

<h2>Conclusion:</h2>

Sybil and her 3 friends will receive ¹/₈ pizza

<h3>Learn more</h3>

Infinite Number of Solutions : brainly.com/question/5450548
System of Equations : brainly.com/question/1995493
System of Linear equations : brainly.com/question/3291576

<h3>Answer details</h3>

Grade: Middle School

Subject: Mathematics

Chapter: Percentage

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point , Multiplication , Division , Exponent , PEMDAS , percentange , percent

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i. 171

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n(U)= 630

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i. Let n(I intersection T ) be X

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<h3>iii. n ( only T)= n( T) - n( I intersection T)</h3><h3> = 468 - 171</h3><h3> = 297</h3>

<h3>Venn- diagram is shown in the attached picture.</h3>

Hope this helps...

Good luck on your assignment...

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