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Lesechka [4]
3 years ago
13

2) 83,97,85,84,96, 80,80,87,91 Mean median and mode

Mathematics
1 answer:
marusya05 [52]3 years ago
4 0

\text {Hi! Let's Solve this Problem!}

\text {Before you find the Mean, Medina and Mode you must put the numbers in order.}

\text {Before: 83, 97, 85, 84, 96, 80, 80, 87, 91}\\\text {After: 80, 80, 83, 84, 85, 87, 91, 96, 97}

\underline {\text {Mean}}

\text {To Find the Mean you must Add all the Numbers then Divide.}

\text {Add:} \text 80+80+83+84+85+87+91+96+97=\fbox {783}}

\text {Divide:} \text {783/9=}

\text {The Mean Is:}

\fbox {87}

\underline {\text Median}}

\text {To find the Median you find the number that's in the middle of the set.}

\text {Put your Left Pointer Finger on 83. Put your Right Pointer Finger on 91.}

\text {Move your Left Finger to the Right. Move your Right Finger to the Left.}

\text {Once your Left Finger makes it to 84 and your Right Finger makes it to 87} \text {it shows that 85 is left in the middle.}

\text {The Median Is:}

\fbox {85}

\underline {\text {Mode}}

\text {Finding the Mode means finding the number} \text { that shows the most in the number set given.}

\text {Since 80 is the number that is showing more than any other number} \text {this tells us that 80 is our Mode.}

\text {The Mode Is:}

\fbox {80}

\text {Best of Luck!}

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74% of 19 year old males are atleast 172 pounds , what percent of the males are not atleast 172 pounds?
swat32

Answer:

<em>The percentage of males are not at least 172 pounds</em>

P(X⁻ ≥ 172) = 0.26

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that 74% of 19 -year -old males are at least 172 pounds

Let 'X' be a random variable in a binomial distribution

P( X≥172) = 74% = 0.74

<em>we have to find that the percentage of males are not at least 172 pounds</em>

<u><em>Step(ii):-</em></u>

<em>The probability of males are not at least 172 pounds</em>

P(X⁻≥172) = 1- P( X≥172)

                 = 1- 0.74

<em>                  = 0.26</em>

<u><em>Final answer:-</em></u>

<em>The percentage of males are not at least 172 pounds</em>

P(X⁻ ≥ 172) = 0.26

<u><em></em></u>

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