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Tom [10]
3 years ago
10

An error has been made in subtracting the two polynomials shown in the work below the problem is (6x^2-4x-5)-(3x^2-7x=2)

Mathematics
1 answer:
MissTica3 years ago
7 0

Answer/Step-by-step explanation:

Let's work out the subtraction of the polynomial to find out where the error is and the correct result we should have.

6x² - 4x - 5

- 3x² - 7x + 2

= [6x² - 3x²] [-4x -(-7x)] [-5 -(+2)]

= 3x² + 3x - 7

The error that was made in the subtraction given in the question was that the negative signs before the terms, 7x and 5 were ignored while subtracting.

The sign is very important, it defines the value of the term.

We can choose to solve the problem in another way shown below:

(6x² - 4x - 5) - (3x² - 7x + 2)

Distributive the negative sign in the second polynomial

6x² - 4x - 5 - 3x² + 7x - 2

Combine like terms

6x² - 3x² - 4x + 7x - 5 - 2

3x² + 3x - 7

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A bucket that weighs 5 lb and a rope of negligible weight are used to draw water from a well that is 60 ft deep. The bucket is f
mestny [16]

Answer:

The value is W= 2640 \  ft \cdot lb

Step-by-step explanation:

From the question we are told that

The weight of the bucket is F =  5 lb

The depth of the well is x_1 =  60 \ ft

The weight of the water is W_w  =  42 lb

The rate at which the bucket with water is pulled is v  = 1.5 \  ft/s

The rate of the leak is r = 0.15 lb/s

Generally the workdone is mathematically represented as

W =  \int\limits^{x_1}_{x_o} {G(x)} \, dx]

Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as

G(x) =  F  +  (W_w- Ix)

Here I is the rate of water loss in lb/ft mathematically represented as

I  = \frac{r}{v}

=> I  = \frac{0.15 }{1.5 }

=> I  = 0.1

So

G(x) =  5  +  (42- 0.1x)

=> G(x) =  47- 0.1x)

So

W =  \int\limits^{60}_{0} {47- 0.1x} \, dx]

=> W =  [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.

=> W= [47(60) - 0.05(60)^2]

=> W= 2640 \  ft \cdot lb

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3 years ago
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