Rearrange the quadratic equation so that it is equal to 0. Then factor the equation.

2 answers:

5 0

First add the 2x to the other side and subtract 24. This leaves you with X^2 -2x -24 =0 Now you can factor it by finding two numbers that multiply to -24 and add to -2. This is -6 and +4. Now set that as (x-6) and (x+4) you can check this answer by using FOIL.... First outer inner last, by multiplying each of those terms and you should get your original equation. I hope that helps!

anyanavicka [17]4 years ago

4 0

The Answers: X²-2X-24 and (X-6)(X+4)

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Take a factor out of the square root:<br> sqrt(3y^2) , where y<0

elena-s [515]

factor took out was $y^2$ , And resultant expression is $y\sqrt{3}$ .

<u>Step-by-step explanation:</u>

Here we need to Take a factor out of the square root: sqrt(3y^2) , where y<0 .Let's do this :

The given expression is sqrt(3y^2) or , $\sqrt{(3y^2)}$

We know that , to take out a factor out of the square root that factor must have a degree in multiple of 2 , as $x^2,x^4,x^16,(x+6)^2,(x-2)^4$ etc . So ,