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tester [92]
2 years ago
7

What's the distributive property for 68 divided by 4

Mathematics
1 answer:
Soloha48 [4]2 years ago
5 0
This is a plain and simple answer. No distributive property here!

68 ÷ 4 = 17

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This figure is made up of a quadrilateral and a semicircle.
Arturiano [62]

Answer:

The correct option is B. The area of the figure is 40.4 units².

Step-by-step explanation:

The line AB divides the figure in two parts one is a rectangle and another is semicircle.

The distance formula is

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The length of AB is

AB=\sqrt{(2+3)^2+(4-2)^2}=\sqrt{25+4}=\sqrt{29}

The length of AD is

AD=\sqrt{(-1+3)^2+(-3-2)^2}=\sqrt{4+25}=\sqrt{29}

Since AB=AD, therefore ABCD is a square. The area of the of square is

A_1=a\times a=\sqrt{29}\times \sqrt{29} =29

The area of square is 29 units².

The area of a semicircle is

A_2=\frac{\pi}{2}r^2

Since AB is the diameter of the semicircle, therefore the radius of the semicircle is

r=\frac{d}{2}=\frac{\sqrt{29}}{2}

The area of the semicircle is

A_2=\frac{3.14}{2}(\frac{\sqrt{29}}{2})^2=40.3825

The area of the figure is

A=A_1+A_2=29+11.2825=40.3825\approx 40.4

Therefore the area of the figure is 40.4 units². Option B is correct.

5 0
3 years ago
There are 10 balls in an urn, numbered from 1 to 10. If 5 balls are selected at random and their numbers are added, what is the
Kisachek [45]

Let B_i denote the value on the i-th drawn ball. We want to find the expectation of S=B_1+B_2+B_3+B_4+B_5, which by linearity of expectation is

E[S]=E\left[\displaystyle\sum_{i=1}^5B_i\right]=\sum_{i=1}^5E[B_i]

(which is true regardless of whether the X_i are independent!)

At any point, the value on any drawn ball is uniformly distributed between the integers from 1 to 10, so that each value has a 1/10 probability of getting drawn, i.e.

P(X_i=x)=\begin{cases}\frac1{10}&\text{for }x\in\{1,2,\ldots,10\}\\0&\text{otherwise}\end{cases}

and so

E[X_i]=\displaystyle\sum_{i=1}^{10}x\,P(X_i=x)=\frac1{10}\frac{10(10+1)}2=5.5

Then the expected value of the total is

E[S]=5(5.5)=\boxed{27.5}

8 0
2 years ago
I need help....Does anybody know the answer?
Alex_Xolod [135]

Answer:

4/5

Step-by-step explanation:

8/15 = 8/15

3/5 = 9/15

2/3 = 10/15

11/15 = 11/15

We see that the pattern is that the terms increase by 1/15 as they move up.

Thus, the next term in the sequence is 12/15, which can be simplified to 4/5.

Let me know if this helps!

3 0
2 years ago
In a box there are 21 identical pieces that have been enumerated using odd numbers from 5 to 45. How many tiles should be drawn
Orlov [11]

These are the only combinations of exactly 3 tiles that add to 33.

5,7,21

5,9,19

5,11,17

5,13,15

7,9,17

7,11,15

9,11,13

All tiles with numbers above 21 do not help you. 23, 25, 27, 29, 31, 33, 35, 37, 39, 41, 43, 45. There are 12 of them.

Every three-number combination must have one of the numbers 5, 7, or 9, so if the six numbers from 13 to 21 are picked, in addition to the 12 higher numbers mentioned above, you already picked 18 tiles, and you still have no solution. To obtain the solutions 5,7,21; 5,9,19; 7,9,17; he needs two more numbers in addition to the 18 he already has, so he needs 20 tiles in total to be guaranteed three of them add to exactly 33.

Answer: 20 tiles

4 0
2 years ago
What is the median of 74,83,79,62,65,73
Allisa [31]

Answer:

Step-by-step explanation:

Median: 73.5

4 0
3 years ago
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