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3 years ago

Simplify the complex numbers: show steps 1) (2i)(6i) 2) (2+i)(3+2i)

Mathematics

1 answer:

asambeis [7]3 years ago

4 0

Here is the answer for this question .

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7 - (-11) = _ <br><br> Please help having trouble with answer

stepladder [879]

Use long addition to evaluate: the answer is 18

8 0

3 years ago

A student has gotten the following grades on his tests. What is the minimum grade he must get on the last test in order to have

arsen [322]

The lowest grade that student could get is a 91 or higher

7 0

3 years ago

Find the approximate area of a triangle that has vertices at A(-4,2),B(6,4)C(3,-1)

MrMuchimi

$area \: of \: triangle \: = \frac{1}{2} |( - 16) - (22)|$
$= \frac{1}{2} | - 44|$
$= | - 22|$
$area \: of \: triangle \: = 22$

6 0

3 years ago

Can someone please help me with this asap ... Please and thank you

OLga [1]

Answer:

Step-by-step explanation:

From the question given in the picture,

a). Since, NR bisects a straight angle ∠MNP,

∠MNR ≅ ∠PNR

m∠MNR + m∠PNR = 180°

2(m∠MNR) = 180°

m∠MNR = 90°

Therefore, ∠MNR and ∠PNR are the right angles.

Since, QN divides ∠MNR in two parts,

Therefore, ∠QNR will be an acute angle (less than 90°).

∠MNR + ∠SNR = ∠MNS

90° + ∠SNR = ∠MNS

Therefore, m∠MNS will be more than 90°.

∠MNS will be an obtuse angle (greater than 90°).

(b). Since, NR divides ∠MNP and ∠QNS,

∠MNR ≅ ∠PNR

∠QNR ≅ ∠SNR

∠MNQ ≅ ∠PNS

(c). m∠MNR = 90°

Since, NR bisects ∠QNS,

∠QNR ≅ ∠RNS

m∠QNR = m∠RNS = 30°

m∠QNR + m∠RNS = 30° + 30°

m∠QNR + m∠RNS = 60°

m∠QNS = 60° [Since, m∠QNS = m∠QNR + m∠RNS]

m∠QNP = m∠QNS + m∠SNP

m∠QNP = m∠QNS + (m∠PNR - m∠SNR)

m∠QNP = 60° + (90° - 30°) = 120°

4 0

3 years ago

How many different twotwo-letter passwords can be formed from the letters

Anna [14]

Answer:

$70$

Step-by-step explanation:

GIVEN: two two-letter passwords can be formed from the letters A, B, C, D, E, F, G and H.

TO FIND: How many different two two-letter passwords can be formed if no repetition of letters is allowed.

SOLUTION:

Total number of different letters $=8$

for two two-letter passwords $4$ different are required.

Number of ways of selecting $4$ different letters from $8$ letters $=^8C_4$

$=\frac{8!}{4!4!}$

$=70$

Hence there are $70$ different two-letter passwords can be formed using $8$ letters.

5 0

3 years ago