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timurjin [86]
2 years ago
12

An experiment consists of tossing a pair of balanced, six-sided dice. (a) Use the combinatorial theorems to determine the number

of sample points in the sample space S. 36 Correct: Your answer is correct. sample points (b) Find the probability that the sum of the numbers appearing on the dice is equal to 6. (Round your answer to four decimal places.)
Mathematics
1 answer:
Bogdan [553]2 years ago
7 0

Answer:

Sample space = 36

P(sum of 6) = 5/36

Step-by-step explanation:

Number of faces on a dice = 6

The sample space, for a toss of 2 dice ; (Number of faces)^number of dice

Sample space = 6^2 = 6*6 = 36

Sum of numbers appearing on the dice = 6

The sum of 6 from the roll of two dice has 5 different outcomes ; Hence, required outcome = 5

Total possible outcomes = sample space = 36

Probability, P = required outcome / Total possible outcomes

P = 5 / 36

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Find the value of x. Write it as a decimal.
makkiz [27]

Answer:

68.5

Step-by-step explanation:

Arc ABE = 360 - 2x

Arc AE = 2x

half the difference between the two arcs is 43

43 = \frac{1}{2} [360 -2x - (2x)]    

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Which set of side lengths is a pythagorean triple
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Several examples of side lengths that are Pythagorean triples are the following with the corresponding side lengths A, B, C:

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4 0
2 years ago
During a field trip, 60 students are put into equal-sized groups. Describe two ways to interpret 60 ÷ 5 in this problem *
sergeinik [125]

Answer:

    x=12 groups

This will give 5 Students each in 12 different equally sized groups

    x'=5groups

This also shows that students can grouped in equal groups of 12 in 5 places

Step-by-step explanation:

From the question we are told that

60 children in equal sized groups

Generally interpreting 60\div 5 can be mathematically represented as

a)

    x=\frac{60}{5}

    x=12 groups

This will give 5 Students each in 12 different equally sized groups

b)

    x'=\frac{60}{12}

    x'=5groups

This also shows that students can grouped in equal groups of 12 in 5 places

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3 years ago
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How do i complete the square for this equation ? x^2+ 8x+y^2-2y=64
liraira [26]
<span>Simplifying x2 + 8x + y2 + -2y = 64
 Reorder the terms: 8x + x2 + -2y + y2 = 64 Solving 8x + x2 + -2y + y2 = 64 Solving for variable 'x'.
 Reorder the terms: -64 + 8x + x2 + -2y + y2 = 64 + -64
  Combine like terms: 64 + -64 = 0 -64 + 8x + x2 + -2y + y2 = 0


 The solution to this equation could not be determined.</span>
4 0
2 years ago
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