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3 years ago

Mehmut is 4 times as old as his brother, but

Mathematics

1 answer:

Serga [27]3 years ago

6 0

Answer:

Mehmut is 8 years old.

Step-by-step explanation:

From the statement we can get the following information, let M be Mehmut's age and b brother's age:

M = 4 * b

M + 1 = 3 * (b + 1)

We replace the first equation in the second and we are left with:

4 * b + 1 = 3 * b + 3

4 * b - 3 * b = 3 - 1

b = 2

Now, we replace to calculate M:

M = 4 * b

M = 4 * 2

M = 8

Mehmut is 8 years old.

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There are eight students in a class. Only one of them has passed Exam P/1 and only one of them has passed Exam FM/2. No student

Svetach [21]

Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

Step-by-step explanation:

Total number of students = 8

Number of student who has passed Exam P/1 = 1

Number of student who has passed Exam FM/2 = 1

No student has passed more than one exam.

According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.

So, Probability will be

$\frac{^6C_3\times ^2C_1}{^8C_4}\\\\=\frac{20\times 2}{70}\\\\=\frac{4}{7}\\\\=0.57$

Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

4 0

3 years ago

Tan^2x+sec^2x=1 for all values of x. <br> true or false?

amid [387]

This is not true.

$\tan^2x+\sec^2x=\dfrac{\sin^2x}{\cos^2x}+\dfrac1{\cos^2x}=\dfrac{1-\cos^2x+1}{\cos^2x}=2\sec^2x-1$

$2\sec^2x-1=1\implies\sec^2x=1\implies\sec x=\pm1\implies x=n\pi$

where is $n$ is any integer. So suppose we pick some value of $x$ other than these, say $x=\dfrac\pi4$ . Then

$\tan^2\dfrac\pi4+\sec^2\dfrac\pi4=1+2=3\neq1$

5 0

3 years ago

Read 2 more answers

Given the piecewise function shown below select all of the statements that are true please help

KengaRu [80]

Answer:

B and D

Step-by-step explanation:

Take a look at all the options x=4, 3, 1, 2 > 0

So, we just care about the domain where x>0, which is $f(x)=x^{2}$ .

Then plug in x we will have the right answer.

5 0

3 years ago

For integers a, b and k, we know that a >12, b > 20 and a < b. If b=7k, what is the value of k ?

Doss [256]

This question is incomplete, the complete question is;

For integers a, b and k, we know that a > 12, b < 20 and a < b. If b=7k, what is the value of k ?

Answer: the value of k = 2

Step-by-step explanation:

Given that;

a > 12

b < 20

a < b

If b = 7k

Now if k = 1 {b = 7k = 7}

b would be equal to 7 but b has to be greater than 20

IT CANT BE

if k = 2 { b = 7k = 14}

b would be equal to 14, a is greater than 12, b has to be less than b; 14 < 20,

a has to be less than than b ( 12 < 14 )

IT IS

if k = 3 {b = 7k = 21}

b would be equal to 21, so b is greater than 20 and a is less than 21

IT CANT BE

Therefore the value of k = 2

5 0

3 years ago

At the city museum, child admission is $5.20 and adult admission is $8.90 . on friday, 159 tickets were sold for a total sales o

Zinaida [17]

Total tickets sold = 159
Total sales = $1100.60
Child admission = $5.20
Adult admission = $8.90

Assumed all 159 tickets are Child admission tickets
Total sales = 159 x 5.2 = $826.80

Difference in amount = $1100.60 - $826.80 = $273.80
The difference must be contributed by the Adult Admission Tickets, which has a difference of $8.90 - $5.20 = $3.70

$273.80 ÷ $3.70 = 74 adult tickets

159 - 74 = 85 child tickets

5 0

3 years ago