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AlekseyPX
3 years ago
5

Need help with this What are the like terms in the equation 5x + 3y + 2x + 3z = 27? ASAP

Mathematics
2 answers:
Delvig [45]3 years ago
7 0

Answer:

C

Step-by-step explanation:

like terms are  terms with the same variable

so like 5x and 2x both have 'x' they are like terms

Tatiana [17]3 years ago
3 0

Answer:

c

Step-by-step explanation:

the like terms are 5x and 2x

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Which expression is equivalent to (3b + 2r) + (4b + r)?
Mice21 [21]

(3b + 2r) + (4b + r)

3b+4b +2r+r

7b +3r

Choice B


4 0
3 years ago
Read 2 more answers
Rewrite y = -(x + 2)2 – 5 in standard form.
xenn [34]

Answer:

y = - x² - 4x - 9

Step-by-step explanation:

Given

y = - (x + 2)² - 5 ← expand (x + 2)² using FOIL

  = - (x² + 4x + 4) - 5 ← distribute parenthesis by - 1

  = - x² - 4x - 4 - 5 ← collect like terms

   = - x² - 4x - 9 ← in standard form

8 0
3 years ago
Solve for x.<br>A. x =9<br>B. x = 3<br>C. x = 4<br>D. x = 27
meriva
Your formula for this is 9^{2} =x(24+x) and 81=24x+ x^{2}.  Get everything on one side of the equals sign, set it equal to 0 and factor.  When you do this you get (x-3)(x+27). The Zero Product Property rule tells us that either x-3 = 0 or x+27 = 0 and that x = 3 and -27.  The only thing in math that will NEVER be negative besides time is distance/length, therefore, x cannot be 27 and has to be 3.
8 0
3 years ago
Please help me ill put the question up for a lot of point, and i will mark as brainliest!!!
sattari [20]

Step-by-step explanation:

(2x³y^-4)^-2 = 1/(4x⁶y^‐8) = y⁸/(4x⁶)

1/(8x⁵y^-7) = y⁷/(8x⁵)

4x^-9y⁴ = 4y⁴/x⁹

so, the whole expression is then

y⁸/(4x⁶) × y⁷/(8x⁵) × 4y⁴/x⁹

4y¹⁹/(32x²⁰) = y¹⁹/(8x²⁰)

so, D is the correct answer.

6 0
2 years ago
This is confusing and makes no sense
Digiron [165]

Answer:

A is the answer

rrrrrrrr

5 0
2 years ago
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