Answer:
12 possibilities
Step-by-step explanation:
In the first urn, we have 4 balls, and all of them are different, as they have different labels, so the group of two red balls r1 and r2 is different from the group of red balls r2 and r3.
The same thing occurs in the second urn, as all balls have different labels.
The problem is a combination problem (the group r1 and r2 is the same group r2 and r1).
For the first urn, we have a combination of 4 choose 2:
C(4,2) = 4!/2!*2! = 4*3*2/2*2 = 2*3 = 6 possibilities
For the second urn, we also have a combination of 4 choose 2, so 6 possibilities.
In total we have 6 + 6 = 12 possibilities.
Answer:
explanations: we multiply with a rational surd
(x-9)*√(x+9)/(√(x-9)*√(x+9)
=(x-9)√(x+9)/
B.( x-9)/√x+3 =( x-9)*(√x-3)/(√x+3)*(√x-3)
= (x-9)*(√x-3)/x-9
=√x-3
Answer:
The value of x = 513
Step-by-step explanation:
Let x, y, and z be the three numbers
Given
Assuming x be the number which is 50% more than the sum of the other two numbers.
i.e.
(150)% of (y+z) = 1.5(y+z)
y + z = x/1.5
As we know that
substituting y + z = x / 1.5 in the equation
Multiply both sides by 1.5
Divide both sides by 2.5
Therefore, the value of x = 513
22% of 50 is 11.
Hope this helps!
Answer:
1/4 or 0.25
Step-by-step explanation:
*I'm assuming you're asking about the probability of this happening...
There are 4 different results you can get when flipping a coin twice...
First Flip: heads
Second Flip: tails
First Flip: heads
Second Flip: heads
First Flip: tails
Second Flip: heads
First Flip: tails
Second Flip: tails
only one of these is heads, then tails, so our probability is
1/4, or 0.25
