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Sati [7]
4 years ago
8

Write a quadratic function h whose zeros are 5 and -7

Mathematics
1 answer:
marin [14]4 years ago
3 0

Quadratic function whose zeros are 5 and -7 is x^2+2x-35=0

Step-by-step explanation:

Write a quadratic function h whose zeros are 5 and -7

If 5 and -7 are zeros of quadratic function then:

x=5 and x=-7

or x-5 = 0 and x+7=0

So, Finding quadratic equation:

(x-5)(x+7)=0\\x(x+7)-5(x+7)=0\\x^2+7x-5x-35=0\\x^2+2x-35=0

So, quadratic function whose zeros are 5 and -7 is x^2+2x-35=0

Keywords: Quadratic Function

Learn more about Quadratic Function at:

  • brainly.com/question/7361044
  • brainly.com/question/9328925
  • brainly.com/question/1357167

#learnwithBrainly

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Tan^2 0+Tan^2 30+Tan^2 60+Sin^2 0​
Ksenya-84 [330]

Answer:

2.996519411885697

Step-by-step explanation:

\tan(20)  +  \tan(230)  +  \tan(260)  +  \sin(20)  = 2.996519411885697

mark me brainliest

5 0
3 years ago
In the sum of two numbers is 20 and their difference is 10 find the numbers​
kodGreya [7K]

"The sum of two numbers is 20" can be translated mathematically into the equation:

x + y = 20.

"... and their difference is 10" can be translated mathematically as:

x - y = 10

We can now find the two unknown numbers, x and y, because we now have a system of two equations in two unknowns, x and y. We'll use the Addition-Subtraction Method, also know as the Elimination Method, to solve this system of equations for x and y by first eliminating one of the variables, y, by adding the second equation to the first equation to get a third equation in just one unknown, x, as follows:

Adding the two equations will eliminate the variable y:

x + y = 20

x - y = 10

-----------

2x + 0 = 30

2x = 30

(2x)/2 = 30/2

(2/2)x = 15

(1)x = 15

x = 15

Now, substitute x = 15 back into one of the two original equations. Let's use the equation showing the sum of x and y as follows (Note: We could have used the other equation instead):

x + y = 20

15 + y = 20

15 - 15 + y = 20 - 15

0 + y = 5

y = 5

CHECK:

In order for x = 15 and y = 5 to be the solution to our original system of two linear equations in two unknowns, x and y, this pair of numbers must satisfy BOTH equations as follows:

x + y = 20 x - y = 10

15 + 5 = 20 15 - 5 = 10

20 = 20 10 = 10

Therefore, x = 15 and y = 5 is indeed the solution to our original system of two linear equations in two unknowns, x and y, and the product of the two numbers x = 15 and y = 5 is:

xy = 15(5)

xy = 75

7 0
3 years ago
to demonstrate probabilities, a mathematics teacher had students draw marbles from a bag which contained 6 yellow marbles and 10
Feliz [49]
4Okay, so here's how you will do the problem.

first lets find out how many marbles there are in total. At first, there are 16 marbles. (6 yellow + 10 blue)

knowing this
P(Yellow) = 6/16. that simplifies to 3/8
P(Blue) = 10/16. that simplifies to 5/8

We can tell these are correct because when added together the probabilities equal 1 (meaning there's no missing probabilities)

Now, 2 yellow marbles and 3 blue marbles are removed.

this means there are now 4 yellow marbles and 7 blue marbles. this brings the total amount of outcomes is 11.

Now
P(yellow) = 4/11
P(blue = 7/11

we can cross multiply or find out the decimal values and compare to find out if the two are equal

3/8.× 4/11
33........32

5/8 × 7/11
55....56

We will come back to what this shows us in a moment

yellow - .375 (3/8) > .36 repeated
blue - .625 (5/8) < .63 repeated

Both methods show that the probability CHANGED. So, YES the probabilities were affected.

in method one, the cross multiplying show that yellow probability goes down and blue probability goes up. Using the decimals shows the same

hope this helps!



8 0
3 years ago
A. Each day, your teacher randomly calls on 5 students in your class of 30. What is the
Anettt [7]

Answer:

The probality is 5/30 or in simpliest form it is 1/6!

Step-by-step explanation:

Hope this helps! Plz give me brainliest

4 0
3 years ago
Please help me thanks.
daser333 [38]

y=(-2x)+5

Step-by-step explanation:

4 0
3 years ago
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