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IgorLugansk [536]
3 years ago
8

It wont let me post a picture of the angles but they are verticle angles and the equations are (3x+8), (5x-40) and it says find

m ABC.
The choices are 24, 56, 80, 90
Mathematics
1 answer:
____ [38]3 years ago
8 0
Vertical angles are equal

5x - 40 = 3x + 8
5x - 3x = 8 + 40
2x = 48
x = 48/2
x = 24

m∠ABC = 3x + 8 = 3 * 24 + 8 = 80°

(or m∠ABC = 5x - 40 = 5 * 24 - 40 = 80°)
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Write your answers as mixed numbers.
max2010maxim [7]
19/2=9 1/2

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7 0
2 years ago
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For the equation given below, evaluate y′ at the point (−2,−1).<br><br> 3xy−3x−12=0.
SSSSS [86.1K]

Answer:

Y'=3xy-3x-12

Y'=F(-2,-1)=0

Step-by-step explanation:

The function of the equation at the point (-2,-1)

is where the equation make the function go to zero:

Y'=3xy-3x-12

Y'=F(-2,-1)=[3(-2)(-1)]-[3(-1)]-12

F(-2,-1)=[6]-[-6]-12

F(-2,-1)=6+6-12

F(-2,-1)=12-12

F(-2,-1)=0

Solving for y

3xy-3x-12=0

y=4/x+x

Making y=0

\frac{4}{x}+x=0

x^{2} =-4

x=-2

So the values make the function go to zero

3 0
2 years ago
A lottery game has balls numbered 1 through 21. What is the probability of selecting an even numbered ball or an 8? Round to nea
Viktor [21]

Answer: 0.476

Step-by-step explanation:

Let A = Event of choosing an even number ball.

B = Event of choosing an 8 .

Given, A lottery game has balls numbered 1 through 21.

Sample space: S= {1,2,3,4,5,6,7,8,...., 21}

n(S) = 21

Then, A= {2,4,6,8, 10,...(20)}

i.e. n(A)= 10

B= {8}

n(B) = 1

A∪B = {2,4,6,8, 10,...(20)} = A

n(A∪B)=10

Now, the probability of selecting an even numbered ball or an 8 is

P(A\cup B)=\dfrac{n(A\cup B)}{n(S)}

=\dfrac{10}{21}\approx0.476

Hence, the required probability =0.476

7 0
3 years ago
A box contains 12 cards numbered from 1 to 12 and 7 face cards. Two cards are randomly drawn from the box without replacement. F
Sergeu [11.5K]

Answer:

i think it is 1/2, or 50%

5 0
3 years ago
Can someoneee please help me
icang [17]

9514 1404 393

Answer:

  37°

Step-by-step explanation:

The diagonals of a rhombus are angle bisectors. Angle 1 matches the other half of angle L.

  ∠1 = 37°

__

Angle 2 is the complement, 53°, and angle 3 is the same as angle 2, 53°.

The diagonals of a rhombus are perpendicular bisectors of each other, so angle 4 is 90°.

7 0
3 years ago
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