Answer:
Quadrilateral ABCD is not a square. The product of slopes of its diagonals is not -1.
Step-by-step explanation:
Point A is (-4,6)
Point B is (-12,-12)
Point C is (6,-18)
Point D is (13,-1)
Given that the diagonals of a square are perpendicular to each other;
We know that the product of slopes of two perpendicular lines is -1.
So, slope(m) of AC × slope(m) of BD should be equal to -1.
Slope of AC = (Change in y-axis) ÷ (Change in x-axis) = (-18 - 6) ÷ (6 - -4) = -24/10 = -2.4
Slope of BD = (Change in y-axis) ÷ (Change in x-axis) = (-1 - -12) ÷ (13 - -12) = 11/25 = 0.44
The product of slope of AC and slope of BD = -2.4 × 0.44 = -1.056
Since the product of slope of AC and slope of BD is not -1 hence AC is not perpendicular to BD thus quadrilateral ABCD is not a square.
Answer:
12
Step-by-step explanation:
3 + x>-9 x=12 15>-9
Answer:
-2
Step-by-step explanation:
Sincwe perpendicular slope are the opposite reciporcal
1) is ABC and XYZ
2) is ABC and RQP I’m not sure about this one though
Answer:
Step-by-step explanation:
z varies inversely
so z=a/x^2
9=a/(2/3)^2
9=a/(4/9)
9=9a/4
a=4
z=4/x^2
z=4/(5/4)^2
z=4/(25/16)
z=64/25
