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3 years ago

If g(x) = -2x + 9, what is the value of x when g(x) = 3?

Mathematics

1 answer:

MissTica3 years ago

7 0

Answer:

x = 3

Step-by-step explanation:

1. Plug 3 into g(x)

3 = -2x + 9

2. Subtract 9 on both sides

-6 = -2x

3. Divide by -2 on both sides to get x by itself

x = 3

I hope this helped :)

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Identify the property’s that justifies the statement: If 4x-3=7, then 4x=10

Alenkasestr [34]

Answer:

Step-by-step explanation:

The equation shown above does not show the substitution property. Instead, it shows the Addition Property of Equation where 3 is added to both of its sides. This is shown below,

4x - 3 = 7

4x - 3 + 3 = 7 + 3

4x = 10

4 0

3 years ago

Which values are solutions to the inequality below?

s344n2d4d5 [400]

Answer:

Step-by-step explanation:

If you find what 11 squared is: 121

All number greater than or equal to 121 will be solutions.

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2 years ago

X - 5 < - 3 <br> Or<br> X + 8 > 2

Alex Ar [27]

Step-by-step explanation:

x-5 < -3

or, x < -3 +5

or, x < 2

Now,

x +8 >2

or, x >2 - 8

or, x >-6

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2 years ago

If start fraction 1 over 3 end fraction is equivalent to 33start fraction 1 over 3 end fraction%, what percent is equivalent to

kotegsom [21]

Answer:

The answer is C 66%

Step-by-step explanation:

5 0

3 years ago

There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is con

grandymaker [24]

Answer:

SAS theorem

Step-by-step explanation:

Given

$\square ABCD$

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$

$\angle BAC = \angle DCA$

Required

Which theorem shows △ABE ≅ △CDE.

From the question, we understand that:

AC and BD intersects at E.

This implies that:

$\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$

and

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$

So, the congruent sides and angles of △ABE and △CDE are:

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$ ---- S

$\angle BAC = \angle DCA$ ---- A

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$ or $\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$ --- S

<em>Hence, the theorem that compares both triangles is the SAS theorem</em>

4 0

2 years ago