2 years ago

What are the coordinates of the image produced by applying the composition / to the point (–5, 4)?

1 answer:

3 0

Its D(5,-4) XD ;p
because I did it and got it right but don't take my word for it just ask the other suggestions <span />

You might be interested in

Find the mean, median, and mode of the data. Which reflects the best measure of the center? 43, 38, 37, 57, 57, 58, 45

Allushta [10]

ANSWER:

mean:47.8

mode:57

median:45

37, 38, 43, 45, 57, 57, 58

8 0

2 years ago

ILL GIVE BRAINLIST ON WHOEVER GETS RIGHT!!!!

tiny-mole [99]

Answer:

The first and third answer I believe.

Step-by-step explanation:

The side with 3 can go over 1.5, since they are both at the same side. It will be equivalent to 4 over 2 because they are also the same side. (1st option)

Multiplying each side by 1/2, does result you to the final image.

3 multiplied by 1/2 is 1.5

4 multiplied by 2 is 2

7 0

2 years ago

Let u = <-9, 4>, v = <8, -5>. Find u - v. <br> URGENT

Pie

To subtract vectors, you simply have to subtract correspondent coordinates.

So, if you have

$u = \langle u_1,\ u_2,\ldots u_n\rangle ,\quad v = \langle v_1,\ v_2,\ldots v_n\rangle$

the subtraction is simply

$u-v = \langle u_1-v_1,\ u_2-v_2,\ldots u_n-v_n\rangle$

So, in your case, we have

$\langle-9,4\rangle-\langle 8,-5\rangle=\langle -9-8, 4+5\rangle=\langle -17,9\rangle$

3 0

2 years ago

Help please

andre [41]

I am pretty sure that it is B

6 0

2 years ago

How do you simplify this problem?

Yuri [45]

1+tan^2(x) = sec^2(x)

sec^2(x) = 1/cos^2(x)

csc(-x) / 1/cos^2(x) =

cos^2(x) csc(-x)

4 0

2 years ago