Answer:
A. It is the ratio of the concentrations of products to the concentrations of reactants.
Explanation:
The equilibrium constant of a chemical reaction is the ratio of the concentration of products to the concentration of reactants.
This equilibrium constant can be expressed in many different formats.
- For any system, the molar concentration of all the species on the right side are related to the molar concentrations of those on the left side by the equilibrium constant.
- The equilibrium constant is a constant at a given temperature and it is temperature dependent.
- The derivation of the equilibrium constant is based on the law of mass action.
- It states that "the rate of a chemical reaction is proportional to the product of the concentration of the reacting substances. "
Answer:
Mass of KNO3 in the original mix is 146.954 g
Explanation:
mass of
in original 254.5 mixture.
moles of ![BaSO_4 = \frac{mass}{Molecular\ Weight}](https://tex.z-dn.net/?f=BaSO_4%20%3D%20%5Cfrac%7Bmass%7D%7BMolecular%5C%20Weight%7D)
moles of
= 0.2926 mol of BaSO4
Therefore,
0.2926 mol of BaCl2,
mass of ![BaCl_2 = mol\times molecular weight](https://tex.z-dn.net/?f=BaCl_2%20%3D%20mol%5Ctimes%20molecular%20weight)
= 60.92 g
the AgCl moles ![= \frac{mass}{Molecular\ Weight}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7Bmass%7D%7BMolecular%5C%20Weight%7D)
![= \frac{199.1}{143.32}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B199.1%7D%7B143.32%7D)
= 1.3891 mol of AgCl
note that, the Cl- derive from both,
so
mole of Cl- f NaCl
mol of Cl-
mol of NaCl = 0.8039 moles
![mass = mol\times Molecular\ Weight = 0.8039 \times 58 = 46.626\ g \ of \ NaCl](https://tex.z-dn.net/?f=mass%20%3D%20mol%5Ctimes%20Molecular%5C%20Weight%20%20%3D%200.8039%20%5Ctimes%2058%20%3D%2046.626%5C%20g%20%5C%20of%20%5C%20NaCl)
then
KNO3 mass = 254.5 - 60.92-46.626 = 146.954 g of KNO_3
Mass of KNO3 in the original mix is 146.954 g
Answer:
C more collision between molecules
Explanation:
increase in heat causes increase in kinetic energy of the particles
You can tell if each side of the equation has the same molar mass.