Answer:
I would say the answer is D
Explanation:
First, we have to know the reaction between HCl and Zn. This is a single replacement reaction as shown below:
2 HCl + Zn → ZnCl₂ + 2 H⁺
The molar mass for zinc is 65.38 g/mol. Convert mass to moles and compute for moles of HCl needed to completely react.
Mole of Zn = 1.4 g * 1 mol/65.38 g = 0.0214 moles Zn
Moles of HCl reacted = 0.0214 mol Zn * ( 2 mol HCl/1 mol Zn) = 0.0428 mol
Moles HCl remaining = 0.12 - 0.0428 = 0/077 moles HCl
Answer: 3390
Explanation:
Since this problem already gives is the equilibrium values, all we have to do is to plug them into the formula for
.
![K_{p} =\frac{[ICl]^2}{[I_{2}][Cl_{2}] }](https://tex.z-dn.net/?f=K_%7Bp%7D%20%3D%5Cfrac%7B%5BICl%5D%5E2%7D%7B%5BI_%7B2%7D%5D%5BCl_%7B2%7D%5D%20%20%7D)
