Answer:
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Explanation:
Answer:
Mass of sodium chloride decomposed = 24.54 g
Explanation:
Given data:
Mass of sodium chloride decomposed = ?
Mass of chlorine gas formed = 15 g
Solution:
Chemical equation:
2NaCl → 2Na + Cl₂
Number of moles of Cl₂:
Number of moles = mass/molar mass
Number of moles = 15 g/ 71 g/mol
Number of moles = 0.21 mol
Now we will compare the moles of Cl₂ with NaCl from balance chemical equation.
Cl₂ : NaCl
1 : 2
0.21 : 2×0.21 = 0.42 mol
Mass of Sodium chloride decompose:
Mass = number of moles × molar mass
Mass = 0.42 mol × 58.44 g/mol
Mass = 24.54 g
is the solubility of the gas when it exerts a partial pressure of 92.4kPa.
<h3>What is Henry's law?</h3>
Mathematically, we can get this from Henry's law
From Henry law;
Concentration = Henry constant × partial pressure
Thus Henry constant = 
Henry constant = 
Hence, is the solubility of the gas when it exerts a partial pressure of 92.4kPa.
Learn more about the Henry's law here:
brainly.com/question/16222358
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