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Licemer1 [7]
3 years ago
11

8.Which arrow or arrows represent a release of carbon dioxide? What process is occurring at the arrow(s) you selected? 9. Which

arrow or arrows indicate a process that cycles carbon from living or nonliving organisms? Describe the process or processes you selected. 10. Which arrow or arrows represent reactions that demonstrate a conservation of mass and energy? Explain your answer.

Chemistry
1 answer:
arsen [322]3 years ago
8 0

Answer:

plant respiration shows arrows where CO2 is released.the arrow is going out of the trees represent the release of carbon dioxide.the arrows from the factories,clouds,water shows the circulation of carbon.

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A 50.0 mL sample of an aqueous H2SO4 solution is titrated with a 0.375 M NaOH solution. The equivalence point is reached with 62
vesna_86 [32]

Answer: The concentration of H_2SO_4 is 0.234 M

Explanation:

According to the neutralization law,

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity H_2SO_4 = 2

M_1 = molarity of H_2SO_4 solution = ?

V_1 = volume of  H_2SO_4 solution = 50.0 ml

n_2 = acidity of NaOH = 1

M_1 = molarity of NaOH solution = 0.375 M

V_1 = volume of  NaOH solution = 62.5 ml

Putting in the values we get:

2\times M_1\times 50.0=1\times 0.375\times 62.5

M_1=0.234M

Therefore concentration of H_2SO_4 is 0.234 M

6 0
2 years ago
A certain object has a volume of 25.0 ml and a mass of 100 g. what is the density of the object
Tpy6a [65]
Density= mass/volume

             = 100/25
density  = 4g/ml
8 0
3 years ago
On a periodic table, element names are represented by:
alina1380 [7]

Answer: Symbols

Explanation:

4 0
3 years ago
Which object is a good conductor of heat and electricity?
Alex

Answer:

C

Explanation:

Metals are good conductors of heat

8 0
2 years ago
How many grams of CO 2 are present in a container with a volume of 5.61 L if the gas exhibits a pressure of 5.66 atm at a temper
Kruka [31]

Answer:

54.72 g

Explanation:

Mass = ?

Volume = 5.61 L

Pressure = 5.66 atm

Temperature = 311 K

The relationship between these equations is given by the ideal gas equation;

PV = nRT

where R = gas constant = 0.0821 atm L K-1 mol-1

n = PV / RT

n = 5.66 * 5.61 / (0.0821 * 311 )

n = 1.2436 mol

Number of moles = Mass / Molar mass

Mass = Number of moles * Molar mass = 1.2436 * 44 = 54.72 g

5 0
3 years ago
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