1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Whitepunk [10]
3 years ago
14

I NEED HELP ASAPPPPPPPPPPPPPPPP

Chemistry
2 answers:
RoseWind [281]3 years ago
8 0

Answer:

i wold think it is C

Explanation:

Aleonysh [2.5K]3 years ago
5 0

Answer:

c i want brainiest

Explanation:

You might be interested in
Chemical reactions _____.
aalyn [17]

1) Chemical reactions produce new substances

Ans (d)

2) The symbol, Δ in a chemical reaction means that heat of supplied to the reaction.

Ans (a)

3) A skeleton equations does not show the reaction stoichiometry, i.e. the relative amounts of reactants and products.

Ans (d)

7 0
3 years ago
Read 2 more answers
A solution with a pH = 13 has approximately how many moles of OH– ions per liter?
GuDViN [60]

Answer :

(A) The number of moles of OH^- ions per liter is, 0.1 moles/L

(B) The number of molecules of H^+ ion is, 6.022\times 10^{10}

(C) The pH of the solution will be, 4

<u>Solution for part A :</u>

First we have to calculate the pOH of the solution.

As we know that,

pH+pOH=14\\\\13+pOH=14\\\\pOH=1

Now we have to calculate the moles of OH^- ion per liter.

pOH=-\log [OH^-]\\\\1=-\log [OH^-]

[OH^-]=0.1moles/L

<u>Solution for part B :</u>

First we have to calculate the H^+ ion concentration.

pH=-\log [H^+]\\\\13=-\log [H^+]

[H^+]=10^{-13}moles/L

Now we have to calculate the number of molecules of H^+ ion

As, 1 mole contains 6.022\times 10^{23} number of molecules of H^+ ion

So, 10^{-13} moles contains 6.022\times 10^{23}\times 10^{-13}=6.022\times 10^{10} number of molecules of H^+ ion

<u>Solution for part C :</u>

pH=-\log [H^+]\\\\pH=-\log (1\times 10^{-4})

pH=4

6 0
4 years ago
Read 2 more answers
Does anyone know how to do this???​
Lelechka [254]

Answer:

2.9 g/cm³

Explanation:

From the question given above, the following data were obtained:

Mass = 236.376 g

Volume = 81.5 cm³

Density =?

Density can be defined as the mass of a substance per unit volume of the substance. It can be expressed mathematically as:

Density = mass /volume

With the above formula, we can obtain the density of the object as shown below:

Mass = 236.376 g

Volume = 81.5 cm³

Density =?

Density = mass /volume

Density = 236.376 / 81.5

Density = 2.9 g/cm³

Thus, the density of the object is 2.9 g/cm³

8 0
3 years ago
Production of Jam from Crushed Fruit in Two Stages. In a process producing jam (C1), crushed fruit containing 14 wt % soluble so
Andrej [43]

Answer:

The total kg from the mixer: m=2222.5 kg

Evaporated water: m_{water ev.}=791.1 kg

Jam produced: m_{jam}=1431.4 kg

Explanation:

Step by step:

1) Kg of mixture from the mixer

It says that crushed fruit is added to the mixer with the sugar and pectin.

The fruit added is 1000 kg

The sugar added is 1.22 kg sugar/1 kg crushed fruit:

m_{sugar}=1000 kg fruit * \frac{1.22 kg sugar}{1 kg fruit}=1220 kg sugar

The pectin added is 0.0025 kg pectin/1 kg crushed fruit:

m_{pectin}=1000 kg fruit * \frac{0.0025 kg pectin}{1 kg fruit}=2.5 kg pectin

The total kg from the mixer:

m=1000 kg fruit + 2.5 kg pectin + 1220 kg sugar=2222.5 kg

2) Evaporated water

To calculate the evaporated water it's important to have in mind that the mix goes from a concentration of 14 wt% to 67 wt%. This difference is because of the evaporated water. So:

Initial: 1000 kg of fruit with 14 wt% of solids

m_{solids}=1000 kg *0.14=140 kg

<em>This amount of solids is constant </em>

Final: The mass of solids is the same but now it represents the 67 wt%

m_{final}=140 kg *\frac{100}{67}=208.9 kg

and

m_{water ev.}=1000kg-m_{final}

m_{water ev.}=1000kg-208.9kg=791.1 kg

3) Jam produced

m_{jam}=m_{final}+m_{pectin}+m_{sugar}=208.9 kg + 1220 kg + 2.5 kg

m_{jam}=1431.4 kg

6 0
3 years ago
Write the formulas of the following compounds:
NemiM [27]

Answer:

(a) barium chloride : BaCl₂ [the cation is barium and anion chloride]  

(b) magnesium-nitride : Mg₃N₂ [Mg is cation and N anion]

(c) sulfur dioxide : SO₂ [ S is cation and O anion]

(d) nitrogen trichloride  : NCl₃

(e) dinitrogen trioxide : N₂O₃ [two nitrogens and three oxygen]

(f) tin(IV) chloride : SnCl₄

Explanation:

The formula of a compound comprises of the symbol of all the elements.

The element or ion having positive charge is written first followed by anion.

The number of any element is represented as subscript in the formula.

(a) barium chloride : BaCl₂ [the cation is barium and anion chloride]  

(b) magnesium-nitride : Mg₃N₂ [Mg is cation and N anion]

(c) sulfur dioxide : SO₂ [ S is cation and O anion]

(d) nitrogen trichloride  : NCl₃

(e) dinitrogen trioxide : N₂O₃ [two nitrogens and three oxygen]

(f) tin(IV) chloride : SnCl₄

7 0
3 years ago
Read 2 more answers
Other questions:
  • Sodium borohydride, NaBH4, and boron trifluoride, BF3, are compounds of boron. What are the shapes around boron in the borohydri
    7·2 answers
  • In the reaction HCl + NaOH → NaCl (aq) + H2O , if 45.0 milliliters of a 2.0 M HCl react in an excess of NaOH, how many grams of
    7·1 answer
  • A glow stick contains a glass vial with chemicals. When the glow stick is bent, the vial breaks
    12·1 answer
  • A sample of mass 6.814 grams is added to another sample weighing 0.08753 grams.
    13·1 answer
  • Childrens chewable Tylenol contains 80.mg of acetaminophen per tablet. If the recommended dosage is 10 .mg/kg , calculate the nu
    14·1 answer
  • Which statement best describes the model that shows a compound?
    13·2 answers
  • Which statement is true about the elements in the periodic table?
    13·2 answers
  • What would happen to an object if the force of gravity on Erath decreased by half
    5·1 answer
  • Describe what it would be like to be an atom
    14·1 answer
  • 69. Sequencing Arrange these hydrates in order of
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!