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Alinara [238K]
3 years ago
11

hi please help i’ll give brainliest if you give a correct answer (please show your long division on paper please :()

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
3 0

Answer:

Attached below

Step-by-step explanation:

sorry couldnt d it on paper ;)

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Justin walked 3 miles north and 6 miles west. starting from the same point, tina walked 2 miles south and 4 miles east. how far
Darya [45]
Basically, Justin and Tina's paths form two right-angled triangles whose hypotenuses(?) form a straight line between their end points. Therefore we need to find the two distances from the starting point and add them.
Justin walked 3 miles north and 6 miles west so his distance from the start is the square root of 9+36 or 45. This can be simplified to 3√5. 
Tina walked 2 miles south and 4 miles east so her distance from the starting point is the square root of 4 + 16 or 20. This can be written as 2√5.
If we add these two distances together we get 5√5. Hence, Justin and Tina are 5√5 miles away from each other.
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Which is greater ? 9/20 or 0.06
bekas [8.4K]
9/20 is greater

9/20 = 0.45
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3 years ago
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What is the answer? I’m new here so please answer it?
11Alexandr11 [23.1K]

Answer:

$258 <u><em>I think</em></u>

Step-by-step Explanation:

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3 years ago
Can someone teach me how to answer this? Thanks!
DaniilM [7]

Answer:

\left( fg\right)  \left( x\right)  =2x^3\sqrt[3]{x}\\\\\left( \frac{f}{g} \right)  \left( x\right)  =\frac{2x^{3}}{\sqrt[3]{x} }

Step-by-step explanation:

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