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antoniya [11.8K]
3 years ago
14

X^2 + 4.7^2 = 13.4^2

Mathematics
1 answer:
tamaranim1 [39]3 years ago
5 0

Answer:

x =   - \: 12.55 \: or \: x = 12.55

Step-by-step explanation:

We want to solve for x in

{x}^{2}  + 4.7^{2}   = 13.4^{2}

We group constants on the right to get:

{x}^{2}  = 13.4^{2}  -  {4.7}^{2}

We apply difference of two squares

{x}^{2}  = (13.4  -  {4.7})(13.4 + 4.7)

{x}^{2}  = 157.47

x =  \pm \sqrt{157.47}

x =  \pm \: 12.55

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alexandr1967 [171]
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3 0
3 years ago
Factorize 3ab + 5ax​
Montano1993 [528]

Answer:

a(3b+5x)

Step-by-step explanation:

Factor 3ab+5ax

3ab+5ax

=a(3b+5x)

MARK ME THE BRAINIEST PLEASE!!

7 0
3 years ago
Verify:<br>cos(2A)=(cotA-tanA)/cscAsecA​
kolbaska11 [484]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

cot A = \frac{cosA}{sinA}, tanA = \frac{sinA}{cosA}, cscA  = \frac{1}{sinA}, secA = \frac{1}{cosA}

Consider the right side

\frac{cotA-tanA}{cscAsecA}

= \frac{\frac{cosA}{sinA}-\frac{sinA}{cosA}  }{\frac{1}{sinA}.\frac{1}{cosA}  }

= \frac{\frac{cos^2A-sin^2A}{sinAcosA} }{\frac{1}{sinAcosA} }

= \frac{cos^2A-sin^2A}{sinAcosA} × sinAcosA ( cancel sinAcosA )

= cos²A - sin²A

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5 0
3 years ago
Without using a calculator determine the number of real zeros of the function f(x) = x^3 + 4x^2 + x -6
hodyreva [135]
Try this:
x³+4x²+x-6=0
1) To re-write the equation into form:
1*x³+4*x²+1*x-6=0, the note 1+4+1=6, it means x=1
2) to re-write the equation into form:
(x-1)(x²+5x+6)=0
(x-1)(x+2)(x+3)=0
3)
\left[\begin{array}{ccc}x-1=0\\x+2=0\\x+3=0\end{array}\right \ \ \textless \ =\ \textgreater \   \left[\begin{array}{ccc}x=1\\x=-2\\x=-3\end{array}\right
Answer: -3;-2;1.
8 0
3 years ago
If x+y=10 and x-y=4 then x2=?
Lera25 [3.4K]
14. 7+3=10 and 7-3=4 so 7x2=14
3 0
3 years ago
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