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3 years ago

Solve the division problem. Round answer to the nearest hundredth. 52.063/9.2

Mathematics

2 answers:

stepladder [879]3 years ago

8 0

52.060 is the answer

Colt1911 [192]3 years ago

6 0

Answer:

52.060 first one 2nd 9.2 i belive

Step-by-step explanation:

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The cost to mail a package is $7 for the first 2 pounds and 30 cents for each additional ounce. Which of the following functions

SOVA2 [1]

A. f(x) = 7 + 0.3x

Just re-read your question! Hope I helped!

5 0

4 years ago

Can you help me how to solve this problem ? thank you

Art [367]

Since BCDEF is regular, we know right away that $x=\dfrac{360}5=72$ because the measures of all exterior angles of any regular polygon add to 360 degrees; they are all of equal measure here, so we divide 360 by 5.

For the pentagon BCIHG, the same is true, which means we have the equation

$\underbrace{72}_x+\underbrace{72}_{\angle_{ext}BCD}+\underbrace{90}_{\angle_{ext}CIH}+\underbrace{(180-y)}_{\angle_{ext}IHG}+\underbrace{68}_{\angle_{ext}HGB}=360\implies y=122$

So $x+y=194$ .

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3 years ago

The American Society of PeriAnesthesia Nurses (ASPAN; www.aspan.org) is a national organization serving nurses practicing in amb

Zigmanuir [339]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data :

114, 261, 319, 183,654,313,58,98,335,324,52,125,342,66,321,893,690,798,201,74,632,216,76,155,161,304,530,1110,93,631,75,344,264,1120,122,45,304,192,316,63

USING CALCULATOR :

The mean(m) of the data: = ΣX/n

n = sample size = 40

m = 12974/40

m = 324.4

Median = ((n + 1)/2) th term = 41/2 = (20 + 21)th term / 2

= (261 + 264) / 2 = 262.5

Standard deviation (s) = sqrt(Σ(x - m)²/n))

s = 281. 74

B.) Coefficient of skewness (Ks) :

3(mean - median) / standard deviation

3(324.4 - 262.5) / 281.74

= 0.66

Mild positive skewness Given a positive skew Coefficient value.

(d-1) Are there any outliers?

Yes

Four outliers

(d-2) What are the limits for outliers? (Round your answers to 1 decimal place. Negative amounts should be indicated by a minus sign.)

Lower bound = Q1 - (1.5 * IQR)

Upper bound = Q3 + (1.5 * IQR)

IQR = Q3 - Q1

Q3 = upper quartile = 343 ; Q1 = 106 ; Q2 = 262.5

IQR = 343 - 106 = 237

Lower bound = 106 - (1.5 * 237) = - 249.5

Upper bound = 343 + (1.5 * 237) = 698.5

-249.5 ≤ X ≤ 698.5

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3 years ago

Which statements are true about using the table of random digits method to identify an SRS? Check all that apply.

adell [148]

Answer:

A,B,E

Step-by-step explanation:

Just did completed this on Ed

8 0

3 years ago

Graph the solution to the inequality 3(x+1)-3<21

kondor19780726 [428]

Answer is x<7 and the graph is in the attachment

5 0

3 years ago

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