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avanturin [10]
3 years ago
12

What two perfect squares does 330 fall between?

Mathematics
2 answers:
horrorfan [7]3 years ago
7 0

Answer:

165

Step-by-step explanation:

corecy

Phantasy [73]3 years ago
5 0

Answer:

A: No, the number 330 is not a perfect square

Step-by-step explanation:

Try these steps first:

A number that is a perfect square never ends in 2, 3, 7 or 8. If your number ends in any of those numbers, you can stop here because your number is not a perfect square.

Obtain the digital root of the number. The digital root essentially is the sum of all of the digits. If you're lost, don't worry, we'll go over each step in more detail below.

All possible numbers that are a perfect square have a digital root of 1, 4, 7, 9.

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A website manager has noticed that during the evening​ hours, about 3.23.2 people per minute check out from their shopping cart
aleksandrvk [35]

Answer:

1.  c. Poisson

2. 0.9592 = 95.92% probability that in any one minute at least one purchase is​ made.

3. 0.0017 = 0.17% probability that no one makes a purchase in the next 2​ minutes.

Step-by-step explanation:

We have only the mean, which means that the Poisson distribution is used to solve this question, and thus the answer to question 1 is given by option c.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Mean of 3.2 minutes:

This means that \mu = 3.2n, in which n is the number of minutes.

2. What is the probability that in any one minute at least one purchase is​ made?

n = 1, so \mu = 3.2.

This probability is:

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-3.2}*3.2^{0}}{(0)!} = 0.0408

So

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0408 = 0.9592

0.9592 = 95.92% probability that in any one minute at least one purchase is​ made.

3. What is the probability that no one makes a purchase in the next 2​ minutes?

2 minutes, so n = 2, \mu = 3.2(2) = 6.4

This probability is P(X = 0). So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-6.4}*6.4^{0}}{(0)!} = 0.0017

0.0017 = 0.17% probability that no one makes a purchase in the next 2​ minutes.

7 0
3 years ago
PLEASE HELP!!!
Marianna [84]

Answer:

c

Step-by-step explanation:

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Answer: $10272.17

Step-by-step explanation: Please see attachment for explanation

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Answer:

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Step-by-step explanation:

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