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GrogVix [38]
3 years ago
10

How many pennies are in one-dollar??

Mathematics
1 answer:
OleMash [197]3 years ago
5 0

Answer:

There are 100 pennies in one dollar.

Step-by-step explanation:

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What value should go in the empty box to complete the calculation for finding the product of 62.834 × 0.45? A)2,213,360 B)2,313,
Aleonysh [2.5K]

Answer:

28.27530

Step-by-step explanation:

Given the expression 62.834 × 0.45, to solve this expression, first we need to convert it to fraction

62.834 = 62834/1000

0.45 = 45/100

Take the product if the resulting fraction:

62.834 × 0.45 = 62834/1000 × 45/100

= (62834×45)/1000×100

= 2,827,530/100,000

= 28.27530

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3 years ago
What are the zeros of the function f(x) =x^2-11x+24 ?
UNO [17]

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there is none

Step-by-step explanation:

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3 years ago
A number y minus 6 is 15
Kitty [74]

Answer:

21

Step-by-step explanation:

15 + 6= 21

so 21-6= 15

there for your answer would be 21

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You need to count all the loaves of bread in the front area. There are 22 loaves of white bread , 17 loaves of wheat bread , and
pickupchik [31]
This is easy first do 22+17=39
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3 years ago
Read 2 more answers
Have Retirement Benefits
charle [14.2K]

Answer:

(a) The probability of the intersection of events "man" and "yes" is 0.55.

(b) The probability of the intersection of events "no" and "man" is 0.10.

(c) The probability of the union of events "woman" or "no" is 0.45.

Step-by-step explanation:

The information provided is:

             Yes    No   Total

Men       275   50     325

Women  150   25      175

Total      425   75      500

(a)

Compute the probability that a randomly selected employee is a man and a has retirement benefits as follows:

P(M\cap Y)=\frac{n(M\cap Y)}{N}=\frac{275}{500}=0.55

Thus, the probability of the intersection of events "man" and "yes" is 0.55.

(b)

Compute the probability that a randomly selected employee does not have retirement benefits and is a man as follows:

P(N\cap M)=\frac{n(N\cap M)}{N}=\frac{50}{500}=0.10

Thus, the probability of the intersection of events "no" and "man" is 0.10.

(c)

Compute the probability that a randomly selected employee is a woman or has no retirement benefits as follows:

P(W\cup N)=P(W)+P(N)-P(W\cap N)=\frac{175}{500}+\frac{75}{500}-\frac{25}{500}=0.45

Thus, the probability of the union of events "woman" or "no" is 0.45.

5 0
3 years ago
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