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Orlov [11]
4 years ago
6

Write an equation of the line that passes through the point (5,-4) and has a slope of 2.

Mathematics
1 answer:
Romashka-Z-Leto [24]4 years ago
6 0

Answer:

Point slope formula: (y + 4) = 2(x - 5)

Slope intercept formula: y = 2x - 14

Step-by-step explanation:

Point slope formula: (y + 4) = 2(x - 5)

Slope intercept formula: y = 2x + b, -4 = 10 + b, b = -14

y = 2x - 14

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How do I solve out 5x188
mihalych1998 [28]

Answer:

940

Step-by-step explanation:

 188

<u>×    5</u>

 940

--------------------------------------------------------

8 * 5 = 40

Carry the 4 to the next 8

8 * 5 = 40

Add the 4 to the 40

40 + 4 = 48

Carry the 4 to the 1

1 * 5 = 5

Add the 4

5 + 9

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*Hope this helps .^.*

5 0
3 years ago
Guys please help me with this question, I’d appreciate it a lot
lutik1710 [3]

Answer:

540

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7 0
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Please answer fast it will be very helpfull please it is a humble requst A samosa costs Rs 5 and a cold drink costs Rs 10. You t
OLEGan [10]
The first answer is 40 second 65 third 56 and then fourth 90
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3 years ago
How to use the break apart strategy to find 247+ 358 in words
r-ruslan [8.4K]
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5 0
3 years ago
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A triangular pyramid has a base with an area of 43 cm squared and lateral faces with bases of 10 cm and heights of 8.6 cm. What
Jet001 [13]

Answer:

The total surface area of triangular pyramid is 172 cm squared

Step-by-step explanation:

Triangular pyramid:

  • Number of faces 4.
  • Number of vertices of a triangular pyramid is 6.
  • The volume  is \frac13 AH. A= area of the pyramid's base and H= height of the pyramid.
  • The surface area of triangular pyramid B+L. B= area of base, L= area of lateral surface.

Given that, the area of the base is 43 cm squared. Lateral faces with bases of 10 cm and heights 8.6 cm.

The 3 sides of the triangular pyramid is triangle in shape.

The area of triangle is \frac12 \times base \times height.

The lateral surface area of the triangular pyramid is

=3(\frac12 \times base \times height)

=3(\frac12\times 10\times8.6) cm squared

=129 cm squared

The total surface area of triangular pyramid is

=Area of the base + lateral surface area

=(43+129) cm squared

=172  cm squared

8 0
4 years ago
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