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Orlov [11]
4 years ago
6

Write an equation of the line that passes through the point (5,-4) and has a slope of 2.

Mathematics
1 answer:
Romashka-Z-Leto [24]4 years ago
6 0

Answer:

Point slope formula: (y + 4) = 2(x - 5)

Slope intercept formula: y = 2x - 14

Step-by-step explanation:

Point slope formula: (y + 4) = 2(x - 5)

Slope intercept formula: y = 2x + b, -4 = 10 + b, b = -14

y = 2x - 14

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A total of
Temka [501]
The answer will be 141 adults
5 0
3 years ago
Find mL 1 and mL 2. ​
lesantik [10]

Answer:

8. ∠1=118° ∠2=118°

9. ∠1=72° ∠2=108°

10. ∠1=127° ∠2=127°

Step-by-step explanation:

8. In this problem, 118° is corresponding to ∠1, meaning they are congruent. ∠2 is supplementary with ∠1, meaning that together, they equal 180°. So, to get ∠2, you must subtract 118° from 180°

9. In this problem, 72° is same side interior with ∠1, meaning they are congruent. ∠2 is supplementary with ∠1, so you do 180°-72°=  108°

10. In this problem, ∠1 is vertical angles with 127°, making them equal to each other. ∠2 is corresponding with 127°, making them also equal.

5 0
2 years ago
Genuinely confused, how would you solve this? (will mark for brainliest!!)
Yanka [14]

Answer:

Length of the bold sector: 40.3ft

Area of the bold sector: 282.08

Step-by-step explanation:

Finding the sector length: Assuming that pi=3.14, the diameter is 87.92 ft. The ratio of the bold section to the whole circumference is 165 to 360. So you need to multiply the circumference by the ratio. (87.92 x 165)/360=40.3

Finding the sector area: Assuming that pi=3.14, the area of the circle is 615.44 sq. ft. The ratio of the sector area to the area of the whole circle is 165:360. (615.44 x 165)/360=282.08, rounded to the nearest 100th.

3 0
3 years ago
Someone help I will make you Brainly
saw5 [17]

Answer:

yep it is b

Step-by-step explanation:

8 0
3 years ago
List the members of P(fa, b, c, d}). Which are proper subsets of fa, b,c, d)?
ankoles [38]

Answer: As i understand, the set is P = {a,b,c,d}

then all the proper subsets are all the sets that belongs to P, that are different of P. Then A is a subset of P if all the elements of A belongs to P, but A is not equal to P

this is:

the sets of one element : {a}, {b}, {c}, {d} and the null set; ∅

sets of two elements: {a,b} , {a,c} , {a.d}, {b,c}, {b,d}, {c,d}

sets of three elements : {a,b,c}, {a,b,d}, {a,c,d}, {b,c,d}

and there arent sets of 4 elements or more.

6 0
3 years ago
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