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Fudgin [204]
3 years ago
6

PLEASE HELP!!

Mathematics
1 answer:
Mariulka [41]3 years ago
6 0
2. 3. 5. are correct

1. and 4. are actually interchanged
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A group of of biped and pentapeds were standing together. There were a total of 33 feet. How Many bipeds and pentapeds can be st
Vitek1552 [10]
Biped means two feet
pentapeds  means five feet

answer:
p=5
b=4

check:
5x5=25
4x2=8
25+8=33
4 0
4 years ago
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Please help I will give brainliest to whoever explains step by step
Evgesh-ka [11]

Answer: In the exact order up to down: 80, 74, 110, 96, 80

Step-by-step explanation:

Do the equation

360=(x-6)+(x+30)+1.2x+x

we can simplify by doing

360=(x-6)+(x+30)+2.2x

=360=x-6+x+30+2.2x

=360=4.2x+24

=336=4.2x

=80=x

x=80

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3 years ago
What is the weight of scissors in grams
lord [1]
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8 0
3 years ago
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Need help with task! Show work if possible~~
Inessa [10]

Answer:

Please see attached picture for full solution.

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3 years ago
An individual who has automobile insurance from a certain company is randomly selected. Let X be the number of moving violations
grin007 [14]

Answer:

(X)      0        1          2          3         4

P(X)   0.17   0.23    0.27    0.24    0.09

F(x)    0.17    0.04    0.65    0.91      1      

Step-by-step explanation:  

Given that;

(X)      0        1          2          3         4

P(X)   0.17   0.23    0.27    0.24    0.09

cumulative distribution function can be calculated by;  be cumulatively up the value of p(x) with the values before it;

so

x      F(x)

0     P(X = 0) = 0.17

1       P(X = 0) + P(X = 1) = 0.17 + 0.23 = 0.4

2      P(X = 0) + P(X = 1) + P(X = 2) = 0.17 + 0.23 + 0.27 = 0.65

3      P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.17 + 0.23 + 0.27 + 0.24 = 0.91

4      P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.17 + 0.23 + 0.27 + 0.24 + 0.09 = 1

Therefore, cumulative distribution function f(x) is;

(X)      0        1          2          3         4

P(X)   0.17   0.23    0.27    0.24    0.09

F(x)    0.17    0.04    0.65    0.91      1      

8 0
3 years ago
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