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stepan [7]
3 years ago
11

Two-fifths of the students in 6th grade are in the band, Of these, one-

Mathematics
1 answer:
Gelneren [198K]3 years ago
3 0

Answer:

1/10 or 10%

Step-by-step explanation:

1/4 x 2/5 = 1/10 (10%)

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An 8% sales tax is applied to a $300 purchase in Texas. What is the total price with tax
natta225 [31]

Answer:

324

Step-by-step explanation:

<u>Step 1:  Find the sales tax </u>

Equation → 300 * 0.08 = x

300 * 0.08 = x

24 = x

<u>Step 2:  Find the total </u>

Purchase + Sales Tax

300 + 24

324

Answer: 324

8 0
3 years ago
Read 2 more answers
If x = 7 and f = 4 and g = 9 and l = 24 and p = 12 and e = 9847493 then what is x ÷ fg X i ÷ p
REY [17]
0.38^• or 7/18. If the x after the g and before the i is a multiplication (btw the ^• is a repeater
3 0
3 years ago
Write x^3-11x^2 in standard form
Vika [28.1K]

Answer:

The answer is x^3 - 11x^2

Step-by-step explanation:

Write in standard form.

Hoped this helped!

brainly, please?

8 0
3 years ago
Help please this is urgent
Licemer1 [7]
25a-5a


Hope this helps!!!!
8 0
3 years ago
Read 2 more answers
A worker at a landscape design center uses a machine to fill bags with potting soil. Assume that the quantity put in each bag fo
defon

Answer:

a) The expected value is given by:

E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11

The variance is given by:

Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333

And the standard deviation is just the square root of the variance and we got:

Sd(x) = \sqrt{0.3333}= 0.5774

b) P(X

And we can use the cumulative distribution function given by:

F(x) = \frac{x-a}{b-a}, a \leq x \leq b

And using this function we got:

P(X

c) P(X>10.5)

And using the complement rule and the cumulative distribution function we got:

P(X>10.5)= 1-P(X

Step-by-step explanation:

For this case we define the random variable X=quantity put in each bag , and we know that the distribution for X is given by:

X \sim Unif (a= 10, b =12)

Part a

The expected value is given by:

E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11

The variance is given by:

Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333

And the standard deviation is just the square root of the variance and we got:

Sd(x) = \sqrt{0.3333}= 0.5774

Part b

For this case we want this probability:

P(X

And we can use the cumulative distribution function given by:

F(x) = \frac{x-a}{b-a}, a \leq x \leq b

And using this function we got:

P(X

Part c

For this case we want this probability:

P(X>10.5)

And using the complement rule and the cumulative distribution function we got:

P(X>10.5)= 1-P(X

3 0
4 years ago
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