Question

A particle moves with constant acceleration along a straight line starting from rest. The percentage increase in its displacement during the 4th second compared to its displacement in the 3rd second (1) 33 % . is (2) 40 % (4) 77 % / (3) 66 % A particle is thrown upward from groun

Answer 1

Answer:

Option 2 is the correct answer.

Explanation:

We have equation of motion s = ut + 0.5at²

Here u = 0 m/s

So, s = 0.5at²

Distance traveled in first second = 0.5 x a x 1² = 0.5 a

Distance traveled in second second = 0.5 x a x 2² - 0.5 x a x 1²= 1.5 a

Distance traveled in third second = 0.5 x a x 3² - 0.5 x a x 2²= 2.5 a

Distance traveled in fourth second = 0.5 x a x 4² - 0.5 x a x 3²= 3.5 a

The percentage increase in its displacement during the 4th second compared to its displacement in the 3rd second

                  $=\frac{3.5a-2.5a}{2.5a}=0.4=40\%$

Option 2 is the correct answer.