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sveticcg [70]
3 years ago
11

The smallest division on the scale of the triple beam balance is .1 g. What is the error in mass for measurements made with this

balance?
Physics
1 answer:
Paladinen [302]3 years ago
3 0

Starting from the definition of a triple beam scale, we could say that this is a measuring instrument whose name comes from its operating system. It is made up of three beams which each carries different weights: One is responsible for measuring what corresponds to increments of 100g, the other to the range of increments of 10g and the third to a single range of 0 to 10g. The error for a triple beam measurement system can be twice the tenth of the minimum count, therefore

\text {Error} = 0.2g

If we took this example into practice if we had a mass of 54.38343g

The error would be:

\text {Error} = 54.38 \pm 0.02g

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If a cart of 8 kg mass has a force of 16 newtons exerted on it what is its acceleration?
ch4aika [34]
Assuming the cart rests on a perfectly smooth and horizontal surface, then we can apply Newton's second law,
F=ma => a=F/m

Acceleration, a = Force/mass = 16 N / 8 kg = 2 m/s^2
6 0
3 years ago
Which type of energy is stored in a capacitor? electric potential energy chemical energy gravitational energy heat energy
Tom [10]

Energy stored in a capacitor is Electric Potential Energy. Capacitor is device used for storing energy. The work done to charge is a capacitor is stored in it in the form of Electrical potential energy. Electrical potential energy is defined as capacity to do work due to the position change. For example, we know fans have capacitor installed in it. When we turn off the fan, it continue moving using the electrical energy stored in the capacitor.

6 0
3 years ago
I need help finding the solution
omeli [17]

Answer:

objects with greater mass should have greater inertia

6 0
3 years ago
A 75-hp (shaft output) motor that has an efficiency of 91.0 percent is worn out and is to be replaced by a high- efficiency moto
daser333 [38]

Convert the shaft ouput from HP to kW

Shaft output = 75HP = 55.93kW

 

1st: Finding for the power consumption based on 55.93kW output

Power consumption (Old) = 55.93kW / .910 = 61.46kW

Power consumption (New) = 55.93kW / .954 = 58.63kW

 

2nd: Total power used in kWh:

Power Used = Power consumption * load factor * Hours:

Power (Old) = 61.46kW * .75 * 4368 = 201343 kWh

Power (New) = 58.63kW * .75 * 4368 = 192072 kWh

Energy saved = 201343 kWh - 192072 kWh = 9,271 kWh

 

3rd: Calculating for the price:

Price = kW-Hr * $/kWh

Price (Old) = 201343kWh * $0.08/kWh = $16107.44

Price (New) = 192072 kWh * $0.08/kWh = $15365.76

Cost saved = $16107.44 - $15365.76 =  $741.68/yr

 

4th: Setting up the cost equation:

Cost over time, F(t) = Motor_Cost + (Price * Number of Years, t)

Cost (Old) = 5449 + 16107.44*t

Cost (New) = 5520 + 15365.76*t

Equate the two to find for t when they cost equally:

5449 + 16107.44*t = 5520 + 15365.76*t

16107.44*t = 15365.76*t +71

16107.44*t - 15365.76*t = 71

741.68*t = 71

t = 71 / 741.68 = .095 years = 35 days

So the payback period is after 35 days.

6 0
3 years ago
Depict the following path: You drive 14 blocks East, 7 blocks North, and 2 blocks West. Use the vertex of the graph (coordinates
horrorfan [7]

Answer:

Displacement = 12\hat{i} +7\hat{j}

Magnitude of displacement = 13.89 units

Angle of displacement = 30.26°

Explanation:

Mark the co-ordinates of each of the end points of the vectors.

The marked co-ordinates are shown below.

Displacement is the shortest distance between two points. Here, displacement between the starting and end points is the vector \overrightarrow{OA}.

Displacement vector for a point A(x,y) from origin O is given as:

\overrightarrow{OA}=(x-0)\hat{i}+(y-0)\hat{j}

Magnitude is given as:

|\overrightarrow{OA}|=\sqrt{x^{2}+y^{2}}

Direction of the vector is given as:

\theta=tan^{-1}\frac{y}{x}

Therefore, displacement vector is:

\overrightarrow{OA}=(12-0)\hat{i}+(7-0)\hat{j}\\ \overrightarrow{OA}=12\hat{i}+7\hat{j}

Magnitude of displacement is given as:

|\overrightarrow{OA}|=\sqrt{x^{2}+y^{2}}\\ |\overrightarrow{OA}|=\sqrt{12^{2}+7^{2}}\\ |\overrightarrow{OA}|=\sqrt{144+49}\\\\ |\overrightarrow{OA}|=13.89

Angle of displacement is:

tan\theta=\frac{y}{x} =\frac{7}{12}\\\theta=tan^{-1}(\frac{7}{12})

\theta=30.26°

8 0
4 years ago
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