1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Genrish500 [490]
3 years ago
6

How do i find the lateral area, total area, and volume of a triangular prism?

Mathematics
1 answer:
drek231 [11]3 years ago
4 0
Total Area = Lateral Area + Area of the Ends
Total Area = Height * Width * Number of Sides + Area of the 2 ends


You might be interested in
The standard equation of a circle with center (h.k) and radius r is (% - hy * (y - Ky = p. Which
zlopas [31]

Answer:

YOUR A DOG ..........................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

3 0
3 years ago
Complete the equation of the line through (6,-6) and (8,8)
melomori [17]
General formula to determine the equation of the line
y - y₁ = m(x - x₁)
(x₁,y₁) is one of the points which lies n the line
m represents the slope

Find the slope
Given:
(x₁,y₁) = (6,-6)
(x₂,y₂) = (8,8)

We could find the slope by using this formula
m = \dfrac{ y_{2} -y_{1} }{ x_{2} -x_{1} }

Plug in the numbers
m = \dfrac{ y_{2} -y_{1} }{ x_{2} -x_{1} }
m = \dfrac{8-(-6)}{8-6}
m = \dfrac{14}{ 2 }
m = 7
The slope is 7

Determine the line equation
Plug one of the points (you could choose any of points given from the question) and the slope to the formula of line equation
y - y₁ = m(x - x₁)
y - (-6) = 7(x - 6)
y + 6 = 7x - 42
y = 7x - 42 - 6
y = 7x - 48
<em>This is the equation of the line</em>
3 0
3 years ago
Given m||n, find the value of x.<br> +<br> (5x+2)<br> (4x+6)°
Anon25 [30]

The required value of x is 4.

7 0
3 years ago
Given the following diagram, find the missing measure. G
jonny [76]

The Given Triangle PMO is a Right Angled Triangle with m∠M = 90°

Given m∠P = 40°

We know that : Sum of Angles in a Triangle = 180°

⇒ m∠P + m∠M  + m∠O = 180°

⇒ 40° + 90° + m∠O = 180°

⇒ 130° + m∠O = 180°

⇒ m∠O = 180° - 130°

⇒ m∠O = 50°

We can notice that m∠O and m∠1 form a Linear Pair (180°)

⇒ m∠O + m∠1 = 180°

⇒ 50° + m∠1 = 180°

⇒ m∠1 = 180° - 50°

⇒ m∠1 = 130°

Last Option is the Answer

6 0
3 years ago
13. A high school has 1600 students. In a random sample of 50 students, 15
Orlov [11]

Answer:

480

Step-by-step explanation:

In 50 student's play station is owned by       =15 student's

∴ In 1 student play station is owned by         =15÷50 student

∴In 1600 student's play station is owned by =(1600×15)÷50 student's

                                                                         =480 student's

∴The number of the student at the high school who

own a Play station is 480

                                     (Ans)

3 0
3 years ago
Other questions:
  • A high school soccer goalie blocked the ball from going into the goal 4 out of 5 times. If the ball was kicked toward the goal 2
    10·1 answer
  • two right triangles share a common side and have equal areas. the hypotenuse of the light green triangle is one of the legs of d
    6·1 answer
  • A craft weighs 6 kg when empty. A lemon weighs about 0.2 kg. For economical shipping the crate with lemons must weigh at least 4
    8·1 answer
  • Carmen is 153.95 cm tall. Marcus is 160.2 cm tall. Who is taller? By how much?
    14·1 answer
  • 1. A day of the week is chosen at random. What is the probability of choosing
    13·2 answers
  • Wanda spent 4 1/8 hours studying last night. She spent 1/3 of the time studying math. How much time did she spend studying math?
    10·1 answer
  • A city has a population of 350,000. The population has decreased by 30% in the past ten years. What was the population of the ci
    14·1 answer
  • Factor completely<br> 12n^3 + 15n^2 + 4n + 5
    8·1 answer
  • Four out of nine dogs weigh less than 20 pounds.
    7·1 answer
  • A civil engineer is mapping the overhead clearance of his family’s property on a coordinate grid. The ground is represented by t
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!