K=5/9(F-32) + 273.15. Solve for F. If you have an answer please leave an explanion, but you Don't have to.
1 answer:
K = (F - 32) + 273.15
To cancel out the 5/9, you can either multiply everything by the denominator and divide it down, or multiply everything by the reciprocal of the fraction (. Multiplying by the reciprocal is definitely easier if you can use a calculator:
K = (F - 32) + 491.67
Subtract 491.67 from both sides:
K - 491.67 = F - 32
Finish off by adding 32 to both sides:
K - 459.67 = F
Therefore, F = K - 459.67.
Hope this helps! :)
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Answer:
( , 3 )
Step-by-step explanation:
Given the 2 equations
y = 9x → (1)
6x - y = - 1 → (2)
Substitute y = 9x into (2)
6x - 9x = - 1, that is
- 3x = - 1 ( divide both sides by - 3 )
x =
Substitute x = into (1) for corresponding value of y
y = 9 × = 3
Solution is ( , 3 )
Answer:
The bulbs should be replaced each 1060.5 days.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
How often should the bulbs be replaced so that no more than 1% burn out between replacement periods?
This is the first percentile, that is, the value of X when Z has a pvalue of 0.01. So X when Z = -2.325.
The bulbs should be replaced each 1060.5 days.