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vovangra [49]
3 years ago
6

K=5/9(F-32) + 273.15. Solve for F. If you have an answer please leave an explanion, but you Don't have to.

Mathematics
1 answer:
Sveta_85 [38]3 years ago
8 0

K = \frac{5}{9}(F - 32) + 273.15

To cancel out the 5/9, you can either multiply everything by the denominator and divide it down, or multiply everything by the reciprocal of the fraction (\frac{9}{5}. Multiplying by the reciprocal is definitely easier if you can use a calculator:

\frac{9}{5}K = (F - 32) + 491.67

Subtract 491.67 from both sides:

\frac{9}{5}K - 491.67 = F - 32

Finish off by adding 32 to both sides:

\frac{9}{5}K - 459.67 = F

Therefore, F = \frac{9}{5}K - 459.67.

Hope this helps! :)

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Quadrilateral ABCD is transformed to create A′B′C′D′. Match the coordinates of A′ with the transformations that create it.
bulgar [2K]

Answer:

The answer is below

Step-by-step explanation:

From the image attached, the coordinates of point A is at (2, -4).

Transformation is the movement of a point from its initial location to a new position. Types of transformation include dilation, reflection, translation and rotation.

If a point A(x, y) is reflected over the x axis, the new point is at  A'(x, -y)

If a point A(x, y) is translated a units right and b units down, the new location is at A'(x + a, y - b)

If a point A(x, y) is dilated by  factor of a, the new location is at A'(ax, ay)

If a point A(x, y) is  rotated 180° clockwise about the origin, the new location is at A'(-x, -y)

Hence:

For Quadrilateral ABCD is reflected over the x-axis, the coordinates of A' is at A'(2, 4)

For Quadrilateral ABCD is translated 2 units right and 1 unit down, the coordinates of A' is at A'(4, -5)

For Quadrilateral ABCD is dilated by a scale factor of 3, the coordinates of A' is at A'(6, -12)

For Quadrilateral ABCD is rotated 180° clockwise about the origin the coordinates of A' is at A'(-2, 4).

Step-by-step explanation:

6 0
3 years ago
Can someone help me with this please ​
alexgriva [62]
The answer to the question is c
6 0
3 years ago
I really need help here I don’t know how to do this
sattari [20]

Answer:

Second box for Justifications: Subtraction Property of equality

Third box for steps: \frac{2}{3} y=-6

Fourth box for steps: \frac{2}{3} y*\frac{3}{2} =-6*\frac{3}{2}

Fourth box for Justifications: Multiplication Property of equality

Fifth box for steps: y=-9

7 0
3 years ago
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