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3 years ago

Find the value of x. Right triangle: Hypotenuse is 9, base is 7.

Mathematics

1 answer:

Aleks [24]3 years ago

5 0

$\sin(x) = \frac{7}{9} \: \: \: \: \: \: \: \\ \: x = \sin - 1( \frac{7}{9} ) \\ x = 51.06$

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Given that f(x) = x2 + 3x + 6 and g(x) = the quantity of x plus two, over three, solve for f(g(x)) when x = 1

MaRussiya [10]

Easy
f(g(1))
evaluate g(1) then plug thatin for x in f(x)
g(1)=(x+2)/3
g(1)=(1+2)/3
g(1)=1

f(g(1))=
f(1)=(1)^2+3(1)+6
f(1)=1+3+6
f(1)=10
f(g(1))=10

3 0

3 years ago

Read 2 more answers

Calculați aplicând distributivitatea înmulțirii fata de adunare și de scădere

solmaris [256]

Răspuns:

7/5;

2 întreg 5/12

Explicație pas cu pas:

6/7 × (2 numere întregi și 5 / 6-1 numere întregi și 1/5)

6/7 * (2 5/6 - 1 1/5)

6/7 * (17/6 - 6/5)

6/7 * (85 - 36) / 30

7/7 * 49/30

1/1 * 7/5

= 7/5

2.)

5/8 × 1 întreg și 2/3 + 11/5

5/8 * (1 2/3 + 11/5)

5/8 * (5/3 + 11/5)

5/8 * (25 + 33) / 15

5/8 * 58/15

1/8 * 58/3

= 58/24

= 2 întreg 10/24

= 2 întreg 5/12

4 0

2 years ago

Need more help - Attached image

mylen [45]

Answer:B

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

System of equations, <br><br> 3x - 6y =2<br><br> 5x + 4y = 1

Anettt [7]

3x-6y=2 (label equation 1)
5x+4y=1 (label equation 2)
-6y=-3x+2 (rearranged equation 1)
y=1/2x-1/3 (label equation 3)
substitute equation 3 into equation 2
5x+4(1/2x-1/3)=1
5x+2x-4/3=1
15x+6x-4=3 (multiplied everything by 3)

21x-4=3
+4 +4
21x=7
x= 7/21
x=1/3
sub x=7/21 into equation 3
y= 1/2(1/3) -1/3
y= -1/6

Therefore x=1/3 and y= -1/6

7 0

3 years ago

A chessboard has an area of 324 square inches. There is an 1-inch border around the 64 squares on the board. What is the length

STALIN [3.7K]

Answer:

Length of one side of the region containing small squares is 16 inches.

Step-by-step explanation:

Given:

Area of the chess board = 324 square inches

Border around 64 -squares on board = 1 inch

We need to find the length containing small squares.

Solution:

Let the length of one side of the chess board be 'L'.

Now we know that;

Border around 64 -squares on board = 1 inch

So we can say that;

Length of the side of the chess board = $L+1+1 = L+2$

Now we know that;

Area of square is equal to square of its side.

framing in equation form we get;

$(L+2)^2=324$

Now taking square root on both side we get;

$\sqrt{(L+2)^2} =\sqrt{324}\\ \\L+2 = 18$

Now subtracting both side by 2 we get;

$L+2-2=18-2\\\\L=16\ in$

Hence Length of one side of the region containing small squares is 16 inches.

5 0

3 years ago