Easy
f(g(1))
evaluate g(1) then plug thatin for x in f(x)
g(1)=(x+2)/3
g(1)=(1+2)/3
g(1)=1
f(g(1))=
f(1)=(1)^2+3(1)+6
f(1)=1+3+6
f(1)=10
f(g(1))=10
Răspuns:
7/5;
2 întreg 5/12
Explicație pas cu pas:
6/7 × (2 numere întregi și 5 / 6-1 numere întregi și 1/5)
6/7 * (2 5/6 - 1 1/5)
6/7 * (17/6 - 6/5)
6/7 * (85 - 36) / 30
7/7 * 49/30
1/1 * 7/5
= 7/5
2.)
5/8 × 1 întreg și 2/3 + 11/5
5/8 * (1 2/3 + 11/5)
5/8 * (5/3 + 11/5)
5/8 * (25 + 33) / 15
5/8 * 58/15
1/8 * 58/3
= 58/24
= 2 întreg 10/24
= 2 întreg 5/12
Answer:B
Step-by-step explanation:
3x-6y=2 (label equation 1)
5x+4y=1 (label equation 2)
-6y=-3x+2 (rearranged equation 1)
y=1/2x-1/3 (label equation 3)
substitute equation 3 into equation 2
5x+4(1/2x-1/3)=1
5x+2x-4/3=1
15x+6x-4=3 (multiplied everything by 3)
21x-4=3
+4 +4
21x=7
x= 7/21
x=1/3
sub x=7/21 into equation 3
y= 1/2(1/3) -1/3
y= -1/6
Therefore x=1/3 and y= -1/6
Answer:
Length of one side of the region containing small squares is 16 inches.
Step-by-step explanation:
Given:
Area of the chess board = 324 square inches
Border around 64 -squares on board = 1 inch
We need to find the length containing small squares.
Solution:
Let the length of one side of the chess board be 'L'.
Now we know that;
Border around 64 -squares on board = 1 inch
So we can say that;
Length of the side of the chess board = 
Now we know that;
Area of square is equal to square of its side.
framing in equation form we get;

Now taking square root on both side we get;

Now subtracting both side by 2 we get;

Hence Length of one side of the region containing small squares is 16 inches.