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Mashutka [201]
3 years ago
9

N a poll to estimate presidential popularity, each person in a random sample of 1,000 voters was asked to agree with one of the

following statements: The president is doing a good job.The president is doing a poor job.I have no opinion.A total of 560 respondents selected the first statement, indicating they thought the president was doing a good job. (a) Construct a 95 percent confidence interval for the portion of respondents who feel the president is doing a good job.
(b) Based on your interval in part, is it reasonable to conclude that a majority (half) of the population believes the president is doing a good job?
Mathematics
1 answer:
Gemiola [76]3 years ago
6 0

Answer:

a) The 95 percent confidence interval for the portion of respondents who feel the president is doing a good job is (0.5292, 0.5908).

b) The lower end of the confidence interval is above 0.5, so yes, it is reasonable to conclude that a majority (half) of the population believes the president is doing a good job.

Step-by-step explanation:

The first step to solve this problem is building the confidence interval. If the lower end of the interval is above 0.5, it is reasonable to conclude that a majority of the population believes that the president is doing a good job.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

a)

A sample of 1000 voters was surveyed, and 560 feel that the president is doing a good job. This means that n = 1000 and \pi = \frac{560}{1000} = 0.56.

We have \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.56 - 1.96\sqrt{\frac{0.56*0.44}{1000}} = 0.5292

The upper limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.56 + 1.96\sqrt{\frac{0.56*0.44}{1000}} = 0.5908

The 95 percent confidence interval for the portion of respondents who feel the president is doing a good job is (0.5292, 0.5908).

b) The lower end of the confidence interval is above 0.5, so yes, it is reasonable to conclude that a majority (half) of the population believes the president is doing a good job.

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<em>95% of confidence interval for the Population</em>

<em>( 6.1386 , 6.8614)</em>

Step-by-step explanation:

<u><em>Step( i ):-</em></u>

<em>Given random sample size 'n' =85</em>

<em>Mean of the sample size x⁻ = 6.5 years</em>

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<u><em>Step(ii):-</em></u>

<em>95% of confidence interval for the Population is determined by</em>

<em></em>(x^{-} - Z_{0.05} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.05} \frac{S.D}{\sqrt{n} })<em></em>

<em></em>(6.5 - 1.96\frac{1.7}{\sqrt{85} } , 6.5 + 1.96 \frac{1.7}{\sqrt{85} })<em></em>

<em>( 6.5 - 0.3614 , 6.5 + 0.3614 )</em>

<em>( 6.1386 , 6.8614)</em>

<u><em>Conclusion</em></u><em>:-</em>

<em>95% of confidence interval for the Population</em>

<em>( 6.1386 , 6.8614)</em>

8 0
3 years ago
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