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3 years ago

Which set of integers is not a Pythagorean triple?

Mathematics

2 answers:

Brums [2.3K]3 years ago

8 0

Option "d" is not a triplet as it does not match the theorem.

bazaltina [42]3 years ago

7 0

A Pythagorean triple consists of three positive integers a, b, and c, such that a^2+b^2= c^2.

You might be interested in

Raj weighs a book and rounds the weights to the nearest tenth. Does this weight round to 1.5 pounds?

Archy [21]

Answer:

Its false

Step-by-step explanation:

4.42 the .42 the 2 is under 5 so it would round up.

7 0

3 years ago

Use the following scenario to answer the question below:

Stolb23 [73]

The bigger engine is about 235.5 cubic centimeters larger than the smaller engine.

We need the answer in cubic centimeters. So let's convert 350 cubic inches to cubic centimeters. We will do it unit conversion way (the long way).

We will write cubic inches as three inches side-by-side

350 in^3

<h3>What is the ratio of the centimeter?</h3>

This way, we can multiply this by the ratio of centimeters to inches [2.54 cm = 1 inch], so that the units cancel and we have cubic centimeters (what we desire).

350 in^3*3.54cm/1in*3.54cm/1in*3.54cm/1in

So, we can cancel the three inches top and bottom thus we have the answer in centimeters cubed. And the value is

350 in^3*3.54cm/1in*3.54cm/1in*3.54cm/1in.

350 in^3*3.54cm/1in*3.54cm/1in*3.54cm/1in=5735.47.

So 350 cubic inches is approximately 5735.5 cubic centimeters (rounded to 1 decimal place).

This is larger than a 5500 cubic centimeters engine.

5735.5-5500=235.5cubic centimeters.

The bigger engine is about 235.5 cubic centimeters larger than the smaller engine.

To learn more about the significant figures visit:

brainly.com/question/24491627

#SPJ1

6 0

2 years ago

3. Define a variable, write an equation, and solve the problem. Carla began a

faust18 [17]

Answer:

Carla has been running 7 miles each day for 13 days.

Step-by-step explanation:

Carla ran 3 miles on her first day, 5 miles on her second day and then 7 miles each day onward.

Let the number of days she ran 7 miles each day = x

Total distance run by Carla = 3 + 5 + 7(x)

= 8 + 7x

If her log book shows that she has run total distance = 99 miles

Equation representing her total run will be,

8 + 7x = 99

7x = 99 - 8

7x = 91

x = $\frac{91}{7}$

x = 13 days

Therefore, Carla has been running 7 miles each day for 13 days.

3 0

3 years ago

Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form

Alex787 [66]

Answer:

$y=-\frac{2}{5}x-\frac{1}{5}$

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

m is the slope

b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

$m = -\frac{2}{5}$

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

$y=-\frac{2}{5}x + b$

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(-3,1). When x of the line is -3, y of the line must be 1.
(2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: $y=-\frac{2}{5}x + b$ . $b$ is what we want, the - $-\frac{2}{5}$ is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

(-3,1). y = mx + b or $1=-\frac{2}{5} * -3 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(-3)$ . $b = -\frac{1}{5}$ .
(2,-1). y = mx + b or $-1=-\frac{2}{5} * 2 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(2)$ . $b = -\frac{1}{5}$ .