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Deffense [45]
3 years ago
14

Will marke bianleast

Mathematics
1 answer:
hjlf3 years ago
4 0

Answer:

(4+4) · 4+4

Step-by-step explanation:

4 + 4 = 8

8 · 4 = 32

32 + 4 = 36

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The answer will be 7,-3

Step-by-step explanation:

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Equation: у них
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the answers for this problem will equal the equation. So it's y=1/3x+5

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What is the best result for h?
Kryger [21]

Answer: First option.

Step-by-step explanation:

To solve for "h" from the given the equation S=2\pi rh+2\pi r^2, you need to:

Apply the Subtraction property of equality and subtract 2\pi r^2 to both sides of the equation.

Then you need to apply the Division property of equality and divide both sides of the equation by 2\pi r.

Then:

S-2\pi r^2=2\pi rh+2\pi r^2-2\pi r^2\\\\S-2\pi r^2=2\pi rh\\\\\frac{S}{2\pi r}-\frac{2\pi r^2}{2\pi r}=\frac{2\pi rh}{2\pi r}\\\\\frac{S}{2\pi r}-r=h

6 0
3 years ago
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A game is played as follows:
mestny [16]
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Find the half range Fourier sine series of the function
worty [1.4K]
The full range is -\pi (length 2L=2\pi), so the half range is L=\pi. The half range sine series would then be given by

f(x)=\displaystyle\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L=\sum_{n\ge1}b_n\sin nx

where

b_n=\displaystyle\frac2L\int_0^Lf(x)\sin\dfrac{n\pi x}L\,\mathrm dx=\frac2\pi\int_0^\pi(\pi-x)\sin nx\,\mathrm dx

Essentially, this is the same as finding the Fourier series for the function

\begin{cases}g(x)=\begin{cases}\pi-x&\text{for }0

Integrating by parts yields

b_n=\dfrac2\pi\left(\dfrac\pi n-\dfrac{\sin n\pi}{n^2}\right)=\dfrac2n

So the half range sine series for this function is simply

f(x)=\displaystyle\sum_{n\ge1}\frac{2\sin nx}n
5 0
3 years ago
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