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Keith_Richards [23]
4 years ago
11

write the 3- digit number That answer the riddle. I have the same ones as Hundreds digit digit. the value of my tens digit is 50

. The value of my ones digit is 4.
Mathematics
1 answer:
attashe74 [19]4 years ago
5 0
Represent the digits as
xyz where they represent whole single digit numbers

same ones place as hundreds
x=z
xyx
value of 10s is 50
one is 4
therefor since 10s is 50 divide by 10 and get 5 for tens digit
y=5
ones is 4
ones=hundred
hundred=4
number is 454
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Help please i need the answer
lora16 [44]

Step-by-step explanation:

but ... you had already correctly answered the first part.

L² + W² = d²

Pythagoras ...

all you needed to do now was do the calculations. no "brainware" needed ...

30² + 10² = d²

900 + 100 = d²

1000 = d²

d = 31.6227766... ≈ 31.6 units

4 0
2 years ago
Let point C be between V and W on VW Given that VW = 61, VC = z + 13, and CW = z + 8, solve for z.
LenKa [72]
VW = VC + CW
61 = z + 13 + z + 8 = 2z + 21
2z = 61 - 21 = 40
z = 40/2 = 20
z = 20.
3 0
3 years ago
Determine whether the lines given are parallel, perpindicular, or neither
mezya [45]
This question has to do with slope. If two lines share the same slope but different points, then there are parallel. If their slopes are negative reciprocals (like -2 and 1/2), then they are perpendicular.
y = 3x - 7 and y = 3x + 1 have different points but both have a slope of 3, where y = mx+b,
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4 0
4 years ago
An experiment involves 16 participants. From these, a group of 4 participants is to be tested under a special condition. How man
zheka24 [161]

Answer:

43,680 ways.

Step-by-step explanation:

We have been given that an experiment involves 16 participants. From these, a group of 4 participants is to be tested under a special condition. We are asked to find the number of groups of 4 participants that can be chosen, assuming that the order in which the participants are chosen is irrelevant.

We will use permutations formula to solve our given problem.

^nP_r=\frac{n!}{(n-r)!}

For our given problem n=16 and r=4.

^{16}P_4=\frac{16!}{(16-4)!}

^{16}P_4=\frac{16!}{12!}=\frac{16*15*14*13*12!}{12!}=16*15*14*13=43,680

Therefore, 4 participants can be chosen in 43,680 different ways.  

6 0
4 years ago
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luda_lava [24]

Answer: 0.3849

Step-by-step explanation:

Given : sample size : n= 51

sample standard deviation : s= 0.46

Significance level : \alpha=1-0.95=0.05

Using chi-square distribution, the critical values will be :

\chi^2_{\alpha/2, n-1}=\chi_{0.025,\ 50}=71.4202

\chi^2_{1-\alpha/2, n-1}=\chi_{0.975,\ 50}=32.3574

Confidence interval for population standard deviation (\sigma) :

\sqrt{\dfrac{s^2(n-1)}{\chi^2_{\alpha/2}}}

Substitute all the values , we get

\sqrt{\dfrac{(0.46)^2(50)}{71.4202}}

Hence, the 95% two-sided confidence interval for σ : 0.3849

8 0
3 years ago
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