Answer:
3.9 in^2
Step-by-step explanation:
Split it up into a top rectangle and a bottom rectangle. Find the area of the top rectangle and subtract the combined area of the two quarter circles.
The area of the rectangle is 6 * 3 = 18. The area of the two quarter circles is the same as the area of one semicircle, and since the radius is 3 you can do:
3^2 * pi / 2 = 9pi/2. As a decimal this would be: 14.14.
Then, you can do rectangle - circle = 18 - 14.14 = 3.86. Rounded to the nearest tenth, this is 3.9
Answer:
18
Step-by-step explanation:
324 = s^2 -->
sqrt324 = s -->
sqrt(2^2 * 9^2) = s -->
2*9 = s -->
18 = s
Answer:
41
Step-by-step explanation:
You want to know when both colleges have the same enrollment. "When" is a time thing so you are going to be solving for x. The number of students is the same and that means you will be solving for y.
Since both ys are equal, you can equate the right side of each equation to each other.
0.046 x + 0.570 = - 0.036x + 2.702 There are a number of ways to go on. The easiest is to dig out your calculator. Add 0.036x to both sides.
0.046x + 0.036x + 0.570 = 2.702
0.082x + 0.570 = 2.702 Now subtract 0.570 from both sides.
0.082x = 2.702 - 0.570
0.082x = 2.132 Divide by 0.084
x = 2.132 / 0.082
x = 26 which means you add 26 onto 1990. The year this took place was 2016
x = 2016 (That's the year there was equality in enrollment). The second one is the only year that gives 2016 as an answer. So you don't have to find y. But we'll do it anyway.
Now you have to solve for y
y = 0.046x +0.57 put 26 in for x
y = 0.046 * 26 + 0.570
y = 1.196 + 0.570
y = 1.766 enrollment numbers were equal, but this is in thousands.
y = 1766 enrollment in actual numbers of students.
Second choice <<<<<===== answer.
