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Drupady [299]
4 years ago
13

Which one of the following activities is considered part of health care operations? A. Administering a stress test B. Reviewing

the competency of health care workers C. Recording a patient's blood pressure and temperature D. Giving a patient her prescribed medication
Physics
1 answer:
Eddi Din [679]4 years ago
7 0
<span>B. Reviewing the competency of health care workers</span> is considered part of health care operations
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Need help with this really lost<br> A<br> B<br> C<br> D
djverab [1.8K]

The answer is "C" because the equator is closest to the sun, because the sun's rays hits the earth surface at the higher angel at the equator and also the sun is directly overhead the equator.


7 0
4 years ago
3. Which of the following is an ionic compound?
svet-max [94.6K]
D. Carbon tetrafluoride
3 0
4 years ago
A mass of 2000 kg is raised 2.0 m in 10 seconds. What is the potential energy of the mass at this height?
Kaylis [27]
Gravitational potential energy is defined as the amount of energy an object possesses at a given height above the Earth's surface. The equation for gravitational energy is E = mgh. Here, m is the mass of the object, g is the acceleration due to gravity, and h is the height above the Earth's surface. Hence, the answer is E = 2000kg x 9.81m/s^2 x 2m = 39240 Joules. 
4 0
4 years ago
A super ball is dropped from a height of 100 feet. Each time it bounces, it rebounds half the distance it falls. How many feet w
Crank

The total distance travelled by the ball after the fourth impact is 275 feet.

<u>Explanation:</u>

Given-

Height, h = 100 feet

Rebounds half the distance

Distance in feet for the fourth time, x = ?

For the first time, the distance travelled by the ball is, x = 100 feet

For the second time, it will bounce up to 50 feet and fall upto 50 feet( half of 100 feet)

So, the distance travelled after the second impact, x = 100 + 50 + 50 = 200 feet

For the third time, it will bounce up to 25 feet and fall upto 25 feet( half of 50 feet)

So, the distance travelled after the third impact, x = 200 + 25 + 25 = 250 feet

For the fourth time, it will bounce up to 12.5 feet and fall upto 12.5 feet( half of 25 feet)

So, the distance travelled after the fourth impact, x = 250 + 12.5 + 12.5 = 275 feet

Therefore, total distance travelled by the ball after the fourth impact is 275 feet.

4 0
4 years ago
Two football players with mass 75kg and 100kg run directly toward each other with speeds of 6 m/s and 8 m/s respectively, If the
Rina8888 [55]

Answer:

2 m/s

Explanation:

From the law of conservation of momentum,

Total momentum before collision = total momentum after collision

mu+m'u' = V(m+m') .................................Equation 1

Where m = mass of the first player, u = initial speed of the first player, m' = mass of the second player, u' = initial speed of the second player, V = combined speed of both players.

Making V the subject of the equation,

V = (mu+m'u')/(m+m')................ Equation 2

Note: Taking the direction of the first player as positive.

Given: m = 75 kg, m' = 100 kg, u = 6 m/s, u' = -8 m/s (opposite the first player),

Substituting into equation 2

V = [(75×6)+(100×(--8))]/(75+100)

V = (450-800)/175

V = 350/175

V = - 2 m/s.

Note: The negative signs tells that the combined speed is in the direction of the second player.

Hence the combined speed of the two players = 2 m/s

8 0
4 years ago
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