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kobusy [5.1K]
3 years ago
13

Which of The following are classiFcatons describing how rock and oTher maTerial movedownslope?a. Fall, b. slide, c. slump, d. cr

eep, e. fow
Physics
1 answer:
nlexa [21]3 years ago
7 0

Answer:

correct answer is Fall slide, slump, creep, flow

Explanation:

solution

we know that Movement of particle under the influence of gravity

so rock and other material move down as gravity.

first rock particle fall down because falls occur very rapidly with high slope after that they slide on the slope and after sliding they slump and it occurs when the rupture surface is curved after slump process they creep.  

after creeping, it can flow particle as it occurs slowly with the low slope with water.

so correct answer is Fall slide, slump, creep, flow

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A system gains 767 kJ of heat, resulting in a change in internal energy of the system equal to +151 kJ. How much work is done?
Crazy boy [7]

Answer:

The work done on the system is -616 kJ

Explanation:

Given;

Quantity of heat absorbed by the system, Q = 767 kJ

change in the internal energy of the system, ΔU = +151 kJ

Apply the first law of thermodynamics;

ΔU = W + Q

Where;

ΔU  is the change in internal energy

W is the work done

Q is the heat gained

W = ΔU  - Q

W = 151 - 767

W = -616 kJ (The negative sign indicates that the work is done on the system)

Therefore, the work done on the system is -616 kJ

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3 years ago
PLEASE HELP
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Explanation:

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3 0
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A motorist driving at 25 meters/second decelerates to
Ilia_Sergeevich [38]
Work done = 0.5*m*[(v2)^2 - (v1)^2]
where m is mass,
v2 and v1 are the velocities.

Given that m = 1.50 x 10^3 kg, v2 = -15 m/s (decelerates), v1 = 25 kg,

Work done = 0.5 * 1.50 x 10^3 * ((-15)^2 - 25^2) = 3 x 10^5 joules

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Tom rides his motorcycle at a speed of 15 meters/second for an hour.
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3 years ago
A 67 kg soccer player uses 5100 kJ of energy during a 2.0 h match. What is the
Oksanka [162]

The  average power produced by the soccer player is  710 Watts.

Given the data in the question;

  • Mass of the soccer player; m = 67kg
  • Energy used by the soccer player; E = 5100KJ = 5100000J
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Power; P =\ ?

Power is simply the amount of energy converted or transferred per unit time. It is expressed as:

Power = \frac{Energy\ converted }{time}

We substitute our given values into the equation

Power = \frac{5100000J}{7200s}\\\\Power = 708.33J/s \\\\Power = 710J/s \ \ \ \ \ [ 2\ Significant\ Figures]\\\\Power = 710W

Therefore, the  average power produced by the soccer player is  710 Watts.

Learn more: brainly.com/question/20953664

8 0
3 years ago
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