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3 years ago

Calculate the acceleration of a train travelling from rest to 24 m/s in 12 seconds.

Physics

1 answer:

AfilCa [17]3 years ago

3 0

Answer:

2 m/s²

Explanation:

Acceleration is equal to velocity divided by the time taken.

24 / 12

= 2

The units for the acceleration is m/s².

The acceleration of the train traveling from rest to 24 m/s in 12 seconds is 2 m/s².

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2 years ago

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3 years ago

A sinusoidally oscillating current I ( t ) with an amplitude of 9.55 A and a frequency of 359 cycles per second is carried by a

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Answer:

$P_{avg} = 6.283*10^{-9} \ W$

Explanation:

Given that;

I₀ = 9.55 A

f = 359 cycles/s

b = 72.2 cm

c = 32.5 cm

a = 80.2 cm

Using the formula;

$\phi = \frac{\mu_o Ic }{2 \pi} In (\frac{b+a}{b})$

where;

$E= \frac{d \phi}{dt}$

$E = \frac{\mu_o}{2 \pi}c In (\frac{b+a}{a}) I_o \omega cos \omega t$

$E_{rms} = \frac { {\frac{\mu_o \ c}{2 \pi} In (\frac{b+a}{a}) I_o (2 \pi f)}}{\sqrt{2}}$

Replacing our values into above equation; we have:

$E_{rms} = \frac { {\frac{4 \pi*10^{-7}*0.325}{2 \pi} In (\frac{72.2+80.2}{80.2}) *9.55 (2 \pi *359)}}{\sqrt{2}}$

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Then the $P_{avg$ is calculated as:

$P_{avg} = \frac{E^2}{R}$

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3 years ago