Answer:
3.059 KJ/mole
Explanation:
check the picture attached for explanation
Answer
given,
angular speed of disk = 32 rad/s
mass dropped, m = 1.3 Kg
radius, r = 0.25 m
new rotational velocity = ?
now,
Initial rotational inertia of the disk
Assuming the mass and the radius of the disk is equal to 7.5 Kg and 0.85 m respectively
now,
Rotational inertia after mass is dropped on it
using angular momentum conservation
I₁ω₁ = I₂ω₂
2.71 x 32 = 2.79 x ω₂
ω₂ = 31 rad/s
new angular velocity of the disk is ω₂ = 31 rad/s
The wavelength of the emitted photon is()= 690nm
<h3>How can we calculate the wavelength of the emitted photon?</h3>
To calculate the wavelength of the photon we are using the formula,
Or,
We are given here,
= The energy difference between the two levels = 1. 8 ev= C.
h= Planck constant = Js.
c= speed of light = m/s.
We have to find the wavelength of the emitted photon = m.
Therefore, we substitute the known parameters in the above equation, we can find that,
Or,
Or, m
Or,=690 nm.
From the above calculation we can conclude that the wavelength of the emitted photon is 690nm.
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Answer:
Induced emf of the wire is 6.36 Volts.
Explanation:
It is given that,
Length of the wire, l = 75 cm = 0.75 m
Magnetic field, B = 0.53 T
Velocity, v = 16 m/s
The wire is moving straight up in the magnetic field. So, an emf is induced in the wire. It is given by :
So, the induced emf of the wire is 6.36 V. Hence, the correct option is (b) "6.36 V".