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ankoles [38]
3 years ago
15

In pottery class, you throw a pot from a lump of wet clay. your pot's mass is 5.5 kg. after the pot is fired, it's mass is 4.9 k

g. the density of wet clay is 1.60 g/cm3 and the density of fired clay is 1.36 g/cm3. what was the volume of your pot before it was fired? what was the volume of the pot after it was fired? express your answer in significant digits.
Physics
1 answer:
kondor19780726 [428]3 years ago
8 0

We can calculate for the volume by taking the ratio of mass and density, that is:

volume = mass / density

 

A. when mass = 5.5 kg = 5500 g; density = 1.60 g/cm^3

volume = 5500 g / (1.60 g/cm^3)

volume = 3,437.5 cm^3

Taking the significant digits:

volume = 3,400 cm^3 = 3.4 L

 

B. when mass = 4.9 kg = 4900 g; density = 1.36 g/cm^3

volume = 4900 g / (1.36 g/cm^3)

volume = 3,602.94 cm^3

Taking the significant digits:

<span>volume = 3,600 cm^3 = 3.6 L</span>

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Answer:A

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4 years ago
Se usa una bombona de He para inflar globos, de volumen 15L con una presión de 200 atm. Si los globos tienen un volumen de 1.5L
Bingel [31]

Answer:

La cantidad de globos llenos es de aproximadamente 1.974 globos

Explanation:

Los parámetros dados son;

El gas utilizado para inflar el globo = Él

El volumen del gas He, V₁ = 15 L

La presión del gas He, P₁ = 200 atm = 20,265,000 Pa

El volumen de cada globo = 1,5 L

La presión del He dentro del globo, P₂ = 770 mmHg = 102,641 Pa

Sea 'V₂', que represente el volumen total que el gas ocupa en todos los globos, y 'x', que represente el número de globos;

Por lo tanto, tenemos;

1,5 · x = V₂

Según la ley de Boyle, tenemos;

P₁ · V₁ = P₂ · V₂

∴ V₂ = P₁ · V₁ / (P₂)

Al introducir los valores conocidos, obtenemos;

V₂ = 20,265,000 Pa × 15 L / (102,641 Pa) = 2,961.53548 L

1,5 L × x = V₂

∴ 1,5 L × x = 2,961,53548 L

x = 2,961.53548 L / (1.5 L) = 1,974.35699 redondeamos hacia abajo para obtener un número entero de globos de la siguiente manera;

El número de globos, x ≈ 1,974 globos.

8 0
3 years ago
which surface would have the greatest friction? low carpet a gym floor a brand new sidewalk or gravel​
jasenka [17]
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7 0
3 years ago
Near the earth's surface, the electric field in the open air has magnitude 150 N/c and is directed down towards the ground. If t
kati45 [8]

Hi there!

Using the equation for the electric field produced by an infinite sheet of charge:

E = \frac{\sigma}{2\epsilon_0}

E = Electric field strength (150 N/C)

σ = Surface charge density (? C/m²)

ε₀ = Permittivity of free space (8.8542× 10⁻¹² C²/Nm²)

We can rearrange the equation to solve for the surface charge density (charge per unit area)

E = \frac{\sigma}{2\epsilon_0}\\\\\sigma = 2E\epsilon_0\\\\\sigma = 2(150)(8.8542*10^{-12}) = \boxed{2.656 \times 10^{-9} \frac{C}{m^2}}

3 0
2 years ago
What is the maximum wavelength of incident light that can produce photoelectrons from silver? The work function for silver is Φ=
zalisa [80]

Answer:

4.24nm

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Explanation:

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λmax = ( hc) /Φ

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1ev = 1.6 * 10^-19

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B.)

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E = 19.89 * 10^-26 / 600 * 10^-28

E = 0.03315 * 10^-26 + 28

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Stopping potential : (3.315 eV - 2.93eV) = 0.385eV

7 0
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