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ankoles [38]
3 years ago
15

In pottery class, you throw a pot from a lump of wet clay. your pot's mass is 5.5 kg. after the pot is fired, it's mass is 4.9 k

g. the density of wet clay is 1.60 g/cm3 and the density of fired clay is 1.36 g/cm3. what was the volume of your pot before it was fired? what was the volume of the pot after it was fired? express your answer in significant digits.
Physics
1 answer:
kondor19780726 [428]3 years ago
8 0

We can calculate for the volume by taking the ratio of mass and density, that is:

volume = mass / density

 

A. when mass = 5.5 kg = 5500 g; density = 1.60 g/cm^3

volume = 5500 g / (1.60 g/cm^3)

volume = 3,437.5 cm^3

Taking the significant digits:

volume = 3,400 cm^3 = 3.4 L

 

B. when mass = 4.9 kg = 4900 g; density = 1.36 g/cm^3

volume = 4900 g / (1.36 g/cm^3)

volume = 3,602.94 cm^3

Taking the significant digits:

<span>volume = 3,600 cm^3 = 3.6 L</span>

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The correct answer among the choices given is the last option. Cora wrapping the copper wire with a thick plastic coating keeps a current from passing out a wire. The plastic wire here serves as an insulator. An insulator is a material that prevents electricity or current to flow out the circuit. In order to lessen the loss of energy.

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3 years ago
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An airplane of mass 39,043.01 flies horizontally at an altitude of 9.2 km with a constant speed of 335 m/s relative to Earth. Wh
Likurg_2 [28]

Answer:

1.2 x 10¹¹ kgm²/s

Explanation:

m = mass of the airplane = 39043.01

r = altitude of the airplane = 9.2 km = 9.2 x 1000 m = 9200 m

v = speed of airplane = 335 m/s

L = Angular momentum of airplane

Angular momentum of airplane is given as

L = m v r

Inserting the values

L = (39043.01 ) (335) (9200)

L =  (39043.01 ) (3082000)

L = 1.2 x 10¹¹ kgm²/s

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3 years ago
A linebacker runs at 3 m/s and collides with a running back running towards him at 3.2
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Answer:b

Explanation:

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A pizza parlor is considering adding taco pizza and Hawaiian pizza to its
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3 years ago
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A 100.0 gram sample of Polonium-210 is contained for 552 days. How many half-lives occur during this period of time, if the half
Leto [7]

Answer:

4 half-lives will occur during this period of time.

Explanation:

Formula used :

a_o=a\times e^{-\lambda t}

\lambda =\frac{0.693}{t_{1/2}}

a=\frac{a_o}{2^n}

where,

a = amount of reactant left after n-half lives and time t

a_o = Initial amount of the reactant.

\lambda = decay constant

t_{1\2} = half life of an isotope

n = number of half lives

We have :

a_o=100.0 g

a = ?

t = 552 days

t_{1/2}=138 days

a=100.0 g\times e^{-\frac{0.693}{138}\times 552}

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6.254 g=\frac{100.0 g}{2^n}

2^n=\frac{100.0 g}{6.254 g}

n = 4

4 half-lives will occur during this period of time.

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4 years ago
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